Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Constraint cloud rounding and loop counts

Example

Take two vertices joined by one edge carrying the empty relation over a nonempty alphabet. The cloud graph has two ports and 129 ordinary edges; the full preprocessing graph has 387 ordinary edges. Their optimal UNSAT values are respectively 1/129 and 1/387, whereas the original UNSAT is one.

Facts & Assumptions

Given: the objects and hypotheses in the statement above.

[F1]

Let G have m=∣E∣>0 ordinary edges, with the fixed nonempty alphabet and paired-loop convention. Its cloud graph G1 is degree 129, has 2m vertices and 129m ordinary edges, and is constructible in polynomial time without changing the alphabet. Put K=max⁡(1,2/h0)=20/7 and c=1/(129K). Then cUNSAT⁡(G)≤UNSAT⁡(G1)≤UNSAT⁡(G)/129. For every labeling τ of G1, plurality decoding Dτ satisfies UNSAT⁡Dτ(G)≤129KUNSAT⁡τ(G1). For an edgeless input use the empty output convention and UNSAT zero. (Regularization preserves value quantitatively).

[F2]

For G with m>0 edges, the full preprocessing graph G2 has 2m vertices, degree 387, and 387m ordinary edges over the same alphabet. It has loops at every vertex and α(G2)≤ρ2:=259+128ρ0387<1. With K=20/7 and c=1/(129K), 129c387UNSAT⁡(G)≤UNSAT⁡(G2)≤UNSAT⁡(G)387. For every port labeling τ, UNSAT⁡τ(G2)=(129/387)UNSAT⁡τ(G1) and UNSAT⁡Dτ(G)≤387KUNSAT⁡τ(G2). Construction and plurality decoding take polynomial time. The edgeless convention has UNSAT zero. (Constraint expander overlay).

Verification

1.1F1

Each original vertex has a singleton cloud. Its degree-128 internal graph consists of 64 ordinary equality loops. There are therefore 128 internal loops and one external empty-relation edge, totaling 129. Every loop is satisfied and the external edge always fails, so every labeling has violation fraction 1/129. This matches the cloud construction's two-port count.

2.1F2step 1.1∎

The degree-128 overlay on two vertices adds 128 ordinary tautological edges, and the 65 additional loops per port add 130 more. Thus the total is 129+128+130=387. Only the empty-relation edge fails for every labeling, yielding 1/387, exactly the overlay factor. This shows the quantitative UNSAT statement does not mean exact preservation of value. A one-symbol alphabet suffices for the example.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources