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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A data-dependent threshold crossing

Example

Take two fair coin observations under the null P0, with the likelihood-ratio process E0=1, E1=ℓ(X1), E2=ℓ(X1)ℓ(X2) and Et=E2 for t≥2, where ℓ(1)=3/2 and ℓ(0)=1/2. Set τ=inf⁡{t≥0:Et≥2}. This is a data-dependent stopping rule. It crosses only on two heads, so P0(τ<∞)=1/4. Since 2=1/α for α=1/2, the crossing probability is below Ville's bound 1/2.

Facts & Assumptions

Given: Two independent fair bits, their prefix filtration, the displayed likelihood-ratio process, and threshold 2. Assume AC for the cited test-supermartingale and optional-sampling conventions.

[F1]

Nonnegative test supermartingales: a test supermartingale is nonnegative, adapted, integrable, supermartingale under the null, and has initial expectation at most one.

[F2]

Ville's inequality for nonnegative test supermartingales: for α∈(0,1), the probability that a nonnegative test supermartingale ever reaches 1/α is at most α.

[F3]

Discrete stopping time: a discrete-time map is a stopping time when each event {τ≤n} belongs to Fn.

[A1]

The Axiom of Choice: AC is inherited by the conditional-expectation clauses used in F1 and F2.

Verification

1.1givenF1A1algebra

The one-step likelihood factor has null conditional mean (3/2+1/2)/2=1 after either possible prefix. Thus E0=1, E1 and E2 are nonnegative, adapted, integrable, and satisfy the supermartingale equality; the process is constant after time two. It is a test supermartingale under P0 by F1.

2.1givenF2F3choosealgebra∎

For every n≥0, {τ≤n}=⋃s=0n{Es≥2}. This is empty for n<2 and equals {X1=X2=1}∈F2⊆Fn for n≥2, so τ is a stopping time by F3. The values (E1,E2) on (X1,X2)=(1,1),(1,0),(0,1),(0,0) are respectively (3/2,9/4),(3/2,3/4),(1/2,3/4),(1/2,1/4). Thus the crossing event {τ<∞} is exactly {X1=X2=1} and has probability 1/4. Since 2=1/α for α=1/2, F2 gives the general upper bound 1/2, and the exact probability is below it.

Depends on

Used by

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