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ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A cloud rounding calculation

Example

Let G be a binary constraint graph, let G1 be its cloud graph as constructed by Degree reduction by expander incidence clouds, and let τ be a labeling of the ports of G1. Suppose that S=10 ports carry a label different from the decoded label of their original vertex, that Uint=4 equality edges inside clouds are violated (counted with multiplicity), and that Uext=2 external edges are violated. Then the bounds of Cloud violations control distance to plurality labels give Uint≥(7/20)⋅10=7/2 and UG≤Uext+S=2+10=12 for the number UG of ordinary edges of G violated by the decoded labeling: the first is consistent with the integer value 4, and the second is an upper bound, so no equality and no stronger local bound is asserted. Passing from these counts to the unsatisfaction fractions of the 387-regular registered graph G2 costs the constant factor of Degree reduction preserves unsatisfaction quantitatively.

Facts & Assumptions

Given: a binary constraint graph G over the fixed alphabet Σ, its cloud graph G1 and registered graph G2, a labeling τ of the ports of G1 with plurality decoding σ=Dτ, and the counts S=10, Uint=4, Uext=2 of the statement.

[F1]

If S is the number of ports whose label differs from the decoded label of their vertex, then the violated equality edges inside the clouds and the violated ordinary edges of G satisfy Uint≥720S and UG≤Uext+S, where Uext counts the violated external edges (Cloud violations control distance to plurality labels).

[F2]

The registered graph G2 is 387-regular with 2∣E(G)∣ vertices, and its unsatisfaction fraction is at least 1/(387K) times that of G with K=20/7; the additive 65 ordinary loops and the overlay edges at every port are tautological, so the count UG of the previous item is a count of edges of G and not of edges of G2 (Degree reduction preserves unsatisfaction quantitatively, Degree reduction by expander incidence clouds).

Verification

technique · direct
1.1

The first inequality of [F1] with S=10 gives Uint≥(7/20)⋅10=7/2, and the labelling has Uint=4, so the bound holds and its slack is 4−7/2=1/2.

F1algebra
1.2

The second inequality of [F1] with Uext=2 and S=10 gives UG≤2+10=12.

F1algebra
2.1

Both bounds are one-sided and the integers Uint=4 and UG∈{0,…,12} are compatible with them, so the numerical data are consistent; the example shows in particular that S=10 ports of disagreement force at least 7/2 (hence at least 4 integer) internal violations and at most 12 ordinary edge violations in G, and nothing of the stronger form UG≤Uext or Uint≥S may be inferred from these bounds.

step 1.1step 1.2algebra
3.1

The comparison with the registered graph is a constant rescaling and not a count identity: by [F2] the fraction of violated edges of G2 is at least 77740 times the fraction of violated ordinary edges of G, and the tautological overlay edges at the ports do not contribute violations in either direction, so the counts Uint, Uext and UG above are statements about the cloud graph G1 and the original graph G.

F2step 2.1algebra∎

Depends on

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Dependency tree · two levels

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