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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-27
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Cloud violations control distance to plurality labels

Statement

Let G be a binary constraint graph over the fixed alphabet Σ with E(G)≠∅, let G1 be its cloud graph as constructed by the degree-reduction map Degree reduction by expander incidence clouds, and let τ be any labeling of the ports of G1 with corresponding plurality decoding σ=Dτ. Write S for the number of ports whose label differs from the decoded label σ(v) of their original vertex v, and let Uint and Uext count the equality edges inside clouds and the external edges that are violated by τ. Then Uint≥720 S,UG≤Uext+S, where UG is the number of ordinary edges of G violated by the decoded labeling σ.

Facts & Assumptions

Given: a binary constraint graph G with E(G)≠∅ over the fixed alphabet, a labeling τ of its cloud graph G1, the decoded labeling σ=Dτ, and the counts S,Uint,Uext,UG above.

[F1]

For any labeling of the cloud graph G1 of a nonempty-edge constraint graph G, decode each original vertex by its cloud's plurality label, using fixed tie breaking. Let S count the ports disagreeing with that label, and let Uint,Uext count violated internal equality and external edges. Then Uint≥(h0/2)S and UG≤Uext+S with h0=7/10, where UG is the decoded violation count in G (Cloud plurality rounding).

[F2]

The cloud graph G1 of the degree-reduction map has one port per incidence, a copy of Hr with equality on every internal edge inside each cloud, one external edge per original edge joining the designated ports, and the same alphabet Σ; the fixed alphabet ordering is used both for the plurality choice of D and for the tie-breaking in the published rounding bound (Degree reduction by expander incidence clouds).

Proof

technique · direct
1.1

The cloud graph and the decoding used here are the ones of [F2], with the same alphabet ordering and the same equality and external relations. Substituting h0=7/10 into the first inequality of [F1] gives Uint≥(7/20)S.

F1F2algebra
1.2

If some cloud contains no port at all, then it contributes neither ports nor edges to the counts; the second inequality of [F1] is a statement about all clouds simultaneously and covers this case. It gives UG≤Uext+S, including S=0 and including the case in which the decoded labeling fails an external edge whose two ports carry labels constant on their clouds.

F1F2
2.1

Both displayed inequalities therefore hold for every labeling τ of the ports of G1, with the constants 7/20 and 1 read off from the published rounding argument; no additional hypothesis on G beyond E(G)≠∅ is used.

step 1.1step 1.2∎

Remarks

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