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Dimer finite-difference bias competes with force-evaluation error

Example

On R2, let V(x,y)=x4/24+y2/2, take the point (0,0) and direction v=e1. The exact Hessian action is ∇2V(0,0)e1=0. With exact gradients, the central dimer estimate is Dϵ=(ϵ2/6)e1. If the two gradient evaluations have errors +ηe1 and −ηe1, each of norm η, the computed estimate becomes D^ϵ=(ϵ2/6+η/ϵ)e1. The truncation bias decreases with ϵ, while this permitted noise contribution increases as ϵ shrinks.

Facts & Assumptions

Given: The potential, point, direction, finite-difference distance ϵ>0, and opposite evaluation errors of magnitude η≥0.

[F1]

The Hessian matrix and critical points of a scalar field: the Hessian is the Jacobian of the gradient; at the origin its action on e1 is zero.

[F2]

Paired force evaluations give a second-order Hessian-vector estimate: for C4 potentials the paired central gradient difference has truncation error O(ϵ2) and force-evaluation contribution at most η/ϵ.

Given: The data in the Example.

Proof

1.1F1givenalgebra

The gradient is ∇V(x,y)=(x3/6,y). Thus ∇V(ϵe1)=(ϵ3/6,0) and ∇V(−ϵe1)=(−ϵ3/6,0). Their central difference is ((ϵ3/3)/(2ϵ),0)=(ϵ2/6)e1. The Hessian at the origin is diag⁡(0,1), so [F1] gives He1=0.

2.1F2step 1.1givenalgebra

Adding the stated force errors changes the numerator by 2ηe1; division by 2ϵ adds ηe1/ϵ. Hence the computed estimate is exactly D^ϵ=(ϵ2/6+η/ϵ)e1. This realizes both contributions in [F2] for this example.

3.1step 2.1algebra∎

For fixed η>0, the deterministic term ϵ2/6 tends to zero as ϵ→0, but the permitted error term η/ϵ grows without bound. Therefore reducing the dimer separation does not monotonically improve the Hessian-vector estimate when force evaluations are inexact.

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