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A corner has no unique tangent and a cusp gives a zero centered chord

Example

Two elementary paths show why regularity and nondegenerate centered chords are explicit hypotheses. The corner path is Rc(s)=(s,0) for s≤0 and Rc(s)=(0,s) for s≥0. The cusp path is Ru(s)=(s2,0). For equal samples at −h and h, the centered chord is R(h)−R(−h).

Facts & Assumptions

Given: The two displayed paths and any h>0 small enough that their samples lie in the stated parameter intervals.

[F1]

Second-order centered and unequal-step tangent estimates assumes a regular C3 curve and a nonzero centered chord before normalizing it.

[F2]

Finite-image projected-gradient string with arc-length redistribution returns geometry-failure if an interior centered chord is zero.

Proof

Given: The paths and sample spacing in the Example.

1.1givenalgebra

For the corner, the one-sided derivatives at 0 are Rc′(0−)=(1,0) and Rc′(0+)=(0,1). They are distinct, so there is no single tangent at the corner. The centered chord is Rc(h)−Rc(−h)=(h,h), whose unit direction is (1,1)/2; it agrees with neither one-sided tangent.

1.2givenalgebra

For the cusp, Ru(h)=Ru(−h)=(h2,0), so its centered chord is exactly zero. Also Ru′(0)=(0,0), so the path is not regular there.

2.1F1F2step 1.1step 1.2∎

The corner violates the differentiability/unique-tangent hypotheses of [F1], while the cusp violates regularity and makes the algorithmic centered direction undefined. By [F2], a finite string update encountering this zero chord must return geometry-failure; neither example can be covered by the second-order normalized-tangent estimate of [F1].

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