Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The inverse infinity row-sum bound is uniform and sharp

Example

For a real matrix B=(bij), define its row-sum matrix norm by ∥B∥row,∞:=max⁡i∑j∣bij∣. For the matrices Ah from Centered finite differences for the zero-Dirichlet boundary-value problem, this norm of Ah−1 is at most 1/8 for every N≥1; at N=3 it is exactly 1/8.

Facts & Assumptions

Given: The row-sum norm just defined, the Dirichlet matrices Ah for N≥1, and the inverse bound of Discrete maximum principle and uniform inverse bound for the Dirichlet stencil.

[F1]

Centered finite differences for the zero-Dirichlet boundary-value problem defines Ah=h−2tridiag⁡(−1,2,−1) with h=1/(N+1).

[F2]

Discrete maximum principle and uniform inverse bound for the Dirichlet stencil proves ∥Ah−1r∥∞≤∥r∥∞/8 for every r∈RN.

[F3]

The triangle inequality gives ∣x+y∣≤∣x∣+∣y∣ for real x,y.

Verification

1.1givenF3algebra

The row-sum expression is nonnegative and equals zero only when every matrix entry is zero; ∥λB∥row,∞=∣λ∣∥B∥row,∞; and [F3] applied entrywise gives ∥B+C∥row,∞≤∥B∥row,∞+∥C∥row,∞. Hence it is a matrix norm.

1.2F1algebra

At N=3, h=1/4 and [F1] gives Ah=16T with T=(2−10−12−10−12). Direct multiplication gives Ah−1=164(321242123), since the displayed integer matrix multiplied by T is 4I3.

2.1givenstep 1.1choosealgebra

Its value equals the induced infinity operator norm sup⁡∥z∥∞≤1∥Bz∥∞: for every such z, each row obeys ∣(Bz)i∣≤∑j∣bij∣, while a row i0 attaining the finite maximum is attained by the vector zj=sgn⁡(bi0j), with sgn⁡(0)=0.

3.1F2step 2.1

By [F2], ∥Ah−1z∥∞≤1/8 whenever ∥z∥∞≤1. Taking the supremum and using step 2.1 shows ∥Ah−1∥row,∞≤1/8 for every N.

4.1step 3.1step 1.2algebra∎

The three absolute row sums of this inverse are 6/64, 8/64, and 6/64, so its row-sum norm is 8/64=1/8. Along with the uniform bound in step 3.1, this proves the stated example and shows its constant is attained.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources