Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-25
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The triangle inequality

Statement

Let F be an ordered field (Ordered field) and let x,y∈F. Then

∣x+y∣≤∣x∣+∣y∣.

Facts & Assumptions

Given: An ordered field F and elements x,y∈F.

[L1]

For every u∈F, −∣u∣≤u≤∣u∣, and ∣u∣ equals u or −u (Basic properties of the absolute value).

[L2]

Order compatible with addition: if a≤b and c≤d, then a+c≤b+d. Order is preserved by adding a constant and by adding inequalities states the STRICT forms and only those (a<b⇒a+c<b+c, and a<b with c<d giving a+c<b+d); the nonstrict form used here is those two together with the cases a=b and c=d, settled by trichotomy, the order being total (Ordered field). Explicitly: if a<b and c<d the second strict form applies; if a<b and c=d the first gives a+c<b+c=b+d; if a=b and c<d the first gives a+c<a+d=b+d; and if a=b and c=d the two sides are equal.

[L3]

Field and order arithmetic: −(a+b)=−a+(−b), and a≤b  ⟺  −b≤−a (Ordered field).

Proof

technique · direct
1.1

By [L1], −∣x∣≤x≤∣x∣ and −∣y∣≤y≤∣y∣.

L1
2.1

Adding the two chains of [step 1.1] with [L2] and using −(∣x∣+∣y∣)=−∣x∣+(−∣y∣) from [L3] gives −(∣x∣+∣y∣)≤x+y≤∣x∣+∣y∣.

step 1.1L2L3
3.1

By [L1] the value ∣x+y∣ equals x+y or −(x+y); both x+y≤∣x∣+∣y∣ and −(x+y)≤∣x∣+∣y∣ hold by [step 2.1] and [L3] (the latter from −(∣x∣+∣y∣)≤x+y), so ∣x+y∣≤∣x∣+∣y∣.

step 2.1L1L3∎

Depends on

Used by

…and 29 more results.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources