Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The reverse triangle inequality

Statement

Let F be an ordered field (Ordered field) and let x,y∈F. Then

∣∣x∣−∣y∣∣≤∣x−y∣.

Facts & Assumptions

Given: An ordered field F and elements x,y∈F.

[L1]

Triangle inequality: ∣a+b∣≤∣a∣+∣b∣ for all a,b∈F (The triangle inequality).

[L2]

For every u∈F, ∣−u∣=∣u∣, and ∣w∣ equals w or −w (Basic properties of the absolute value).

Proof

technique · direct
1.1

Applying [L1] with a=x−y and b=y gives ∣x∣=∣(x−y)+y∣≤∣x−y∣+∣y∣, so ∣x∣−∣y∣≤∣x−y∣.

L1
1.2

Applying [L1] with a=y−x and b=x, and using ∣y−x∣=∣x−y∣ from [L2], gives ∣y∣≤∣y−x∣+∣x∣=∣x−y∣+∣x∣, so ∣y∣−∣x∣≤∣x−y∣.

L1L2
2.1

By [L2] the value ∣∣x∣−∣y∣∣ equals ∣x∣−∣y∣ or −(∣x∣−∣y∣)=∣y∣−∣x∣, and each of these is ≤∣x−y∣ by steps 1.1 and 1.2, so ∣∣x∣−∣y∣∣≤∣x−y∣.

step 1.1step 1.2L2algebra∎

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources