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TheoremStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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Linearity, monotonicity, the absolute-value estimate and coordinate-slice additivity for the Riemann integral in Rm\mathbb{R}^m

Statement

Let Q=j<m[aj,bj]Q=\prod_{j<m}[a_j,b_j] be nondegenerate. For integrable f,g:QRf,g:Q\to\mathbb R and scalars α,β\alpha,\beta, the function αf+βg\alpha f+\beta g is integrable and its integral is αQf+βQg\alpha\int_Qf+\beta\int_Qg. If fgf\le g, then QfQg\int_Qf\le\int_Qg. Also f|f| is integrable and QfQf|\int_Qf|\le\int_Q|f|. If ar<c<bra_r<c<b_r, cutting QQ at the coordinate hyperplane xr=cx_r=c gives two nondegenerate subrectangles; integrability on QQ is equivalent to integrability on both restrictions, and their integral values add to the integral over QQ.

Facts & Assumptions

Given: The stated integrable functions on the nondegenerate rectangle, and, for coordinate-slice additivity, a strictly interior cut ar<c<bra_r<c<b_r.

[L3]

uvuv\bigl||u|-|v|\bigr|\le|u-v|, the reverse triangle inequality on the real line (The reverse triangle inequality, Absolute value in an ordered field, Basic properties of the absolute value).

Proof

technique · direct
1.1

Refine grids good for ff and gg. Cellwise supremum and infimum estimates make the gap of αf+βg\alpha f+\beta g at most α|\alpha| times the gap of ff plus β|\beta| times that of gg; tagged-sum linearity identifies the value.

L1L2
1.2

Termwise fgf\le g gives monotonicity of every tagged sum and hence of integrals. By [L3], the oscillation of f|f| on a cell is no larger than that of ff, so f|f| is integrable; fff-|f|\le f\le|f| then gives the absolute-value estimate.

L1L3given
1.3

Insert the cut coordinate into the grid. [L2] splits every Darboux or tagged sum into the two subrectangle sums. Good grids splice conversely, proving integrability on QQ exactly when both restrictions are integrable, and proving additivity.

L1L2
2.1

These arguments establish all clauses with positively oriented rectangles.

step 1.1step 1.2step 1.3

Depends on

Used by

Dependency tree · next 3 levels

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Sources