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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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The divergence at a point is the limit of outward flux per unit volume

Statement

Let OR3 be open, let F:OR3 be C1 and let pO. For each mN let a finite gluing of elementary solid regions be given whose union E(m) satisfies E(m)O, pE(m) and cont(E(m))>0, and suppose diam(E(m))0. Then

limm1cont(E(m))E(m)F,n=divF(p),

that is: for every rational ε>0 there is M such that every mM satisfies

1cont(E(m))E(m)F,ndivF(p)<ε.

Positive content is required only so that the quotient is defined; no relation between the content and the diameter is assumed.

Facts & Assumptions

Given: The open OR3, the C1 field F on O, the point pO, and for each m the finite gluing with union E(m)O containing p, of positive content, with diam(E(m))0.

[F1]

The divergence of a C1 field is divG=i<niGi; a C1 map has continuous first partial derivatives, so divG is continuous (Divergence and curl of a C1 vector field, Ck Euclidean maps and diffeomorphisms).

[F3]

For a nonempty bounded A in a metric space, diam(A)=sup{d(a,b):a,bA} (Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space), the metric on R3 being d(a,b)=ab2 (The Euclidean inner product x,y=k<nxkyk on Rn).

[F4]

A map between metric spaces is continuous at a point when for every real ε>0 there is a real δ>0 such that points within δ of it have images within ε (Continuity of a map between metric spaces, at a point and globally, in the ε-δ form).

[F5]

A sequence of reals converges to x when for every rational ε>0 there is K with xkx<ε for all kK (Limits and Cauchy sequences of reals).

[L1]

For a finite gluing with union E and outer presentation Σout and a C1 field G on an open set containing E, EdivG=EG,n (The divergence theorem for finite gluings of elementary solid regions).

[L3]

For integrable f,g on a nondegenerate rectangle and scalars α,β: αf+βg is integrable with integral αf+βg; if fg then fg; and f is integrable with ff (Linearity, monotonicity, the absolute-value estimate and coordinate-slice additivity for the Riemann integral in Rm).

[L4]

Every continuous real function on a compact Jordan measurable set is Riemann integrable over it (A continuous real function on a compact Jordan measurable set is Riemann integrable over that set).

Proof

technique · direct
1.1

For each m the set E(m) is compact and Jordan measurable by [L2], and divF is continuous on O by [F1], hence integrable over E(m) by [L4]. Since F is C1 on the open OE(m), [L1] gives E(m)F,n=E(m)divF.

givenF1L1L2L4
1.2

Let ε>0 be rational. The function divF is continuous at p by [F1], so [F4] with the real number ε/2 supplies δ>0 such that every qO with qp2<δ satisfies divF(q)divF(p)<ε/2. Since diam(E(m))0, there is M with diam(E(m))<δ for every mM.

givenF1F3F4F5
2.1

Fix mM. Since pE(m), every qE(m) has qp2diam(E(m))<δ by [F3], so step 1.2 bounds divFdivF(p) by ε/2 on E(m). By [L3] and [F2], E(m)divF(p)=divF(p)cont(E(m)), and E(m)divFdivF(p)cont(E(m))=E(m)(divFdivF(p))E(m)ε2=ε2cont(E(m)).

step 1.1step 1.2F2F3L3
3.1

Dividing the estimate of step 2.1 by the positive number cont(E(m)) and substituting step 1.1 gives 1cont(E(m))E(m)F,ndivF(p)ε2<ε for every mM. As ε was an arbitrary positive rational, [F5] gives the asserted limit.

step 2.1F5

Remarks

  • No shape hypothesis is needed. The content cancels between the estimate and the quotient, so nothing forces the solids to be balls, cubes or comparable to their diameters. What is needed is that each carries the gluing data, that each contains p, and that the diameters vanish.

  • Positive content is a hypothesis about the quotient, not about the estimate. Step 2.1 holds whatever cont(E(m)) is; step 3.1 divides by it. A solid of content zero would make the left-hand side undefined rather than make the estimate fail.

Depends on

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Sources