Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedverified 2026-09-23 (gpt-6-sol)
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Positivity of the oriented integral

Statement

Let ω∈Ωcn(M) be nonnegative on the positive determinant ray of an oriented smooth manifold. Then ∫Mω≥0, and ω≠0 implies ∫Mω>0. Here the compact-support integral is the choice-free finite-chart value, equal to the global partition value whenever that construction is available.

Facts & Assumptions

[F1]

Finite chart localization of compactly supported top forms, including boundary constructs a finite nonnegative chart localization near any compact support, proves its signed chart sum independent of that localization, and proves nonnegativity and strict positivity for a nonzero nonnegative top form, including genuine boundary and dimension zero. Its value agrees with the global partition integral under countable choice.

Proof

Given: The objects and hypotheses in the statement above.

1.1F1

Apply the finite localization of [F1] to K=supp⁡ω. In every chart its nonnegative weight multiplies a nonnegative signed coefficient, so each chart integral is nonnegative and so is their finite sum.

2.1F1step 1.1

If n≥1 and ωp≠0, at least one finite weight is positive at p. Its signed coefficient is continuous and positive there, hence bounded below by some c>0 on a small interior rectangle of positive volume, including when p lies on a genuine boundary face. Its chart integral is positive; the other terms are nonnegative.

3.1F1step 1.1step 2.1∎

For n=0 every signed point summand is nonnegative and a nonzero form has a strictly positive summand. The zero form and the empty manifold give zero. Agreement with the global integral when it is constructed by a partition follows from [F1].

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