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The volume of a glued elementary solid is a third of the outward flux of the position field
Statement
Let a finite gluing of elementary solid regions be given, with union and outer boundary presentation , and let be the position field on . Then the content of the solid is a third of the outward flux of the position field through its boundary:
Moreover each of the three single-coordinate fields , and satisfies
Facts & Assumptions
Given: The finite gluing with union and outer presentation , and the position field .
The divergence of a field is (Divergence and curl of a vector field).
For , , and has th coordinate and the others (The Euclidean inner product on , The standard list with and for is an ordered basis of ; hence , and is the zero space with basis and dimension ).
For a finite gluing with union and outer presentation and a field on an open set containing , (The divergence theorem for finite gluings of elementary solid regions).
For a finite gluing, is compact and Jordan measurable (Internal faces cancel and volume integrals add when elementary solid regions are glued, Finite gluings of elementary solid regions and their outward boundary presentation).
For integrable on a nondegenerate rectangle and scalars , the function is integrable with integral (Linearity, monotonicity, the absolute-value estimate and coordinate-slice additivity for the Riemann integral in ).
Proof
The position field has , so is when and otherwise; these are continuous on , so is there and [F1] gives at every point. By [L2] the set is compact and Jordan measurable, so by [F2].
For each the field has th coordinate and the other two coordinates by [F3], so its only nonvanishing first partial derivative is ; it is therefore on with divergence by [F1].
Applying [L1] with , which is on the open set , gives , and by [L3] with , and step 1.1 this is . Dividing by gives the first identity.
Applying [L1] with the field of step 1.2 gives by step 1.1, for each of the three directions .
Steps 2.1 and 2.2 are the asserted identities.
Remarks
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The solid is Jordan measurable because its pieces are, not by assumption. Step 1.1 takes that from [L2]; without it the symbol would not denote anything and would not exist.
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The orientation is what fixes the sign. Reversing every patch of the presentation negates the right-hand sides and would give a negative content. That the presentation of a glued elementary solid carries the outward normal is Every patch of an elementary solid region's presentation is a graph face in some direction, and at interior base points its normal is outward applied to each piece, and the companion examples page checks the sign against the known volume of a ball.
Depends on
- The divergence theorem for finite gluings of elementary solid regions
- Divergence and curl of a $C^1$ vector field
- A bounded set is Jordan measurable iff its indicator is Riemann integrable, and the integral is its Jordan content
- The Riemann integral of a bounded function over a bounded Jordan measurable set
- Finite gluings of elementary solid regions and their outward boundary presentation
- Internal faces cancel and volume integrals add when elementary solid regions are glued
- The Euclidean inner product $\langle x,y\rangle = \sum_{k<n} x_k y_k$ on $\mathbb{R}^n$
- Linearity, monotonicity, the absolute-value estimate and coordinate-slice additivity for the Riemann integral in $\mathbb{R}^m$
- The standard list $e : n \to F^{n}$ with $e_i(i) = 1_F$ and $e_i(j) = 0_F$ for $j \ne i$ is an ordered basis of $F^{n}$; hence $\dim_F F^{n} = n$, and $F^{0}$ is the zero space with basis $\varnothing$ and dimension $0$
Used by
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Sources
- M. Corral, Vector Calculus, chapter 4 (LibreTexts), Example 4.2 (standard reference, not scraped)
- J. Feldman, A. Rechnitzer and E. Yeager, CLP-4 Vector Calculus (University of British Columbia), section 4.2 (standard reference, not scraped)