Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Squaring is monotone on the nonnegatives

Statement

Let F be an ordered field. For a,b≥0:

a<b  ⟺  a2<b2,a≤b  ⟺  a2≤b2.

More generally, for arbitrary a,b∈F, a2<b2  ⟺  ∣a∣<∣b∣.

Facts & Assumptions

Given: Elements a,b of an ordered field F.

[L1]

For a positive factor s>0 and any t: t>0  ⟺  st>0; this is Sign rules for products and monotonicity of multiplication (the rule c>0⇒(x<y  ⟺  xc<yc) taken at x=0, y=t, c=s, using 0⋅s=0, Multiplication by zero: 0⋅a=0).

[L2]

Trichotomy: for a,b exactly one of a<b, a=b, a>b holds; and a sum of two nonnegatives with at least one positive is positive (Ordered field).

[L3]

∣x∣≥0 and ∣x∣2=x2 for every x (Basic properties of the absolute value).

Proof

technique · direct
1.1

The difference factors as b2−a2=(b−a)(b+a).

algebra
2.1

If a,b≥0 and a<b, then b>0, so b+a>0 by [L2], and b−a>0; by [L1] with s=b+a and t=b−a, (b−a)(b+a)>0, i.e. a2<b2.

L1L2step 1.1
2.2

If a,b≥0 and a2<b2, then b2−a2>0, so a,b are not both zero and b+a>0 by [L2]; by [L1] with s=b+a, from (b−a)(b+a)=b2−a2>0 we get b−a>0, i.e. a<b.

L1L2step 1.1
3.1

Hence for a,b≥0, a<b  ⟺  a2<b2.

step 2.1step 2.2
4.1

The ≤ form follows by trichotomy: for a,b≥0, applying step 3.1 to the nonnegatives b,a gives a≤b  ⟺  ¬(b<a)  ⟺  ¬(b2<a2)  ⟺  a2≤b2.

step 3.1L2
5.1

For arbitrary a,b, [L3] gives ∣a∣,∣b∣≥0 with ∣a∣2=a2 and ∣b∣2=b2; applying step 3.1 to ∣a∣,∣b∣ yields a2<b2  ⟺  ∣a∣2<∣b∣2  ⟺  ∣a∣<∣b∣.

step 3.1L3∎

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources