Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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The Dirichlet kernel at zero and away from zero

Example

For each N≥1,

DN(0)=2N+1,

while

DN ⁣(14N+2)=1sin⁡(π/(4N+2))>0,DN ⁣(34N+2)=−1sin⁡(3π/(4N+2))<0.

So the Dirichlet kernel has a removable peak at 0 and already changes sign at two explicit nearby points.

Facts & Assumptions

Given: An integer N≥1.

[L1]

The Dirichlet kernel is DN(t)=∑∣k∣≤Nek(t) (Dirichlet and Fejer kernels).

[L2]

For t∉Z, DN(t)=sin⁡((2N+1)πt)sin⁡(πt), and DN(0)=2N+1 (Closed form and size bounds for the Dirichlet kernel).

Verification

technique · direct
1.1L1L2algebra

At t=0, [L1] gives DN(0)=∑∣k∣≤Nek(0)=∑∣k∣≤N1=2N+1, which agrees with the removable value recorded in [L2].

2.1L2algebra∎

The numbers (4N+2)−1 and 3(4N+2)−1 are not integers, so [L2] applies. Since (2N+1)π/(4N+2)=π/2 and 3(2N+1)π/(4N+2)=3π/2, the numerator is respectively 1 and −1. The denominators are positive because their angles lie in (0,π). Hence the two displayed signs follow.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources