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A distributed heat source has an exact box-constrained optimum

Statement

Assume Countable Choice. Let E=Ω=(0,1), V=H01(0,1), U=H=L2(0,1), and a(u,v)=∫01(u′v′+uv) dx. Let Bq be the L2 load functional v↦∫01qv dx, set f=0, qa=0, qb=1, and α=1. Put q∗(x)=12sin⁡(πx) and u∗(x)=q∗(x)/(π2+1), which solve the state equation. Set p∗(x)=−q∗(x) and ud(x)=u∗(x)+12(π2+1)sin⁡(πx). Define J(q)=12∥u(q)−ud∥L22+12∥q∥L22. Then q∗ is the unique optimal control, and its adjoint is p∗.

Facts & Assumptions

Given: The one-dimensional coercive elliptic control problem, the admissible box 0≤q≤1, and the exactly defined target ud.

[F1]

The state and adjoint equations have unique weak solutions under the bounded coercive form hypotheses (Well-posedness of elliptic control state and adjoint equations).

[F2]

For α>0, an admissible q satisfying (B∗p(q)+αq,v−q)U≥0 for every v∈Qad is the unique minimizer (Existence, uniqueness, and variational inequality for elliptic PDE control).

Verification

1.1F1givenalgebra

The form is the full H1 inner product, so it is bounded and coercive with constants one, and ∣⟨Bq,v⟩∣≤∥q∥2∥v∥H1. Since f=0, −u∗′′+u∗=q∗, and u∗(0)=u∗(1)=0, integration by parts first for compactly supported smooth tests and then by H01 density gives a(u∗,v)=(q∗,v)L2 for every v∈H01(0,1); uniqueness in [F1] identifies the state. Since −p∗′′+p∗=−12(π2+1)sin⁡(πx)=u∗−ud and p∗ has zero boundary values, the same argument verifies the adjoint equation.

2.1F2step 1.1givenalgebra∎

The load identity gives (B∗p∗,r)U=⟨Br,p∗⟩=(p∗,r)U for every r∈U, hence B∗p∗=p∗. Since 0≤q∗≤1/2, it is admissible, and B∗p∗+αq∗=p∗+q∗=0. Thus its variational inequality holds with equality for every admissible comparison control, and [F2] makes q∗ the unique minimizer.

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