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An empty incoming boundary requires zero handles
Example
Assume . Let . If a nonempty compact connected triad has , then every handle decomposition relative to begins with at least one -handle: a -handle with attaches along the nonempty sphere , which cannot be embedded in the empty initial boundary. The sphere has the presentation with exactly one -handle and one -handle. This shows that the nonempty-incoming-boundary hypothesis in the elimination proposition cannot be dropped.
Facts & Assumptions
Given: A nonempty compact connected triad with and with and , and a finite handle decomposition of relative to with indices and attaching embeddings .
Handle decomposition relative to the incoming boundary: a decomposition relative to is a finite ordered list of handles attached successively, the first to the boundary of the initial stage; when the initial stage is the empty manifold and the first handle attaches to the empty set.
Index zero handles create components: a -handle attaches along the empty set and adds one disjoint -disk component.
Index n handles cap boundary spheres: an -handle attaches along its whole boundary sphere . For it fills a boundary component diffeomorphic to ; for its attaching is a pair of boundary points, possibly in different components.
Connected cobordisms admit presentations without superfluous zero handles: Assume . A connected triad with nonempty incoming boundary admits a presentation relative to that boundary with no -handles; when the incoming boundary is empty, exactly the -handles needed to create the components remain.
Morse functions and handle decompositions correspond: Assume . Every finite handle decomposition of a compact triad relative to its incoming face is induced by an adapted excellent Morse function with one critical point per handle, of the same index (and conversely).
For the attaching region is nonempty: for , and for . For the attaching region is .
Verification
The initial stage of any presentation relative to is empty, so its boundary is empty as well, and the first attaching embedding must map into it; hence the first handle must have empty attaching region. By [A1] this happens exactly for : the attaching region of a -handle is , while a -handle with has nonempty attaching region and cannot be attached to the empty initial boundary. Therefore every presentation begins with at least one -handle.
A connected manifold with empty incoming boundary needs at least one -handle, since the first stage is empty and only a -handle creates a component by [F2]; and by [F4] exactly the -handles needed to create the components of remain, which for connected is one -handle. Hence the elimination of -handles is impossible when , and the hypothesis in [F4] is necessary.
The sphere example: the closed -sphere is the union of two closed disks glued along their common boundary sphere, . Read the first disk as a -handle and the second as an -handle attached along its whole boundary , which by [F3] fills the whole boundary sphere and produces . This presentation has exactly one -handle and one -handle, and no other handles, in agreement with the fact that a connected manifold with keeps exactly one -handle by step 2.1 and that the -handle closes the remaining boundary sphere.
By [F5] the presentation of step 3.1 is realized by a Morse function on the triadic description of with two critical points, of indices and ; this is the standard round-sphere height function with a minimum and a maximum. In particular the sphere carries a presentation with exactly one -handle as claimed, and the presentation of any connected triad with empty incoming boundary must begin with a -handle, so the elimination proposition cannot be applied without change in that case.
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Sources
- C. T. C. Wall, Differential Topology (Cambridge Studies in Advanced Mathematics 156), Sections 5.1-5.4, printed pp. 129-148 (standard reference, not scraped)
- John Milnor, Lectures on the h-Cobordism Theorem (notes by L. Siebenmann and J. Sondow), Sections 2-4, printed pp. 10-48 (standard reference, not scraped)