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An empty incoming boundary requires zero handles

Example

Assume ACω. Let n≥1. If a nonempty compact connected triad has M0=∅, then every handle decomposition relative to M0 begins with at least one 0-handle: a k-handle with k≥1 attaches along the nonempty sphere Sk−1×Dn−k, which cannot be embedded in the empty initial boundary. The sphere Sn has the presentation with exactly one 0-handle and one n-handle. This shows that the nonempty-incoming-boundary hypothesis in the elimination proposition cannot be dropped.

Facts & Assumptions

Given: A nonempty compact connected triad (W;M0,M1) with n≥1 and ACω with M0=∅ and dim⁡W=n, and a finite handle decomposition of W relative to M0 with indices k1,…,kr and attaching embeddings h1,…,hr.

[F1]

Handle decomposition relative to the incoming boundary: a decomposition relative to M0 is a finite ordered list of handles attached successively, the first to the boundary of the initial stage; when M0=∅ the initial stage is the empty manifold and the first handle attaches to the empty set.

[F2]

Index zero handles create components: a 0-handle attaches along the empty set S−1×Dn and adds one disjoint n-disk component.

[F3]

Index n handles cap boundary spheres: an n-handle attaches along its whole boundary sphere Sn−1. For n≥2 it fills a boundary component diffeomorphic to Sn−1; for n=1 its attaching S0 is a pair of boundary points, possibly in different components.

[F4]

Connected cobordisms admit presentations without superfluous zero handles: Assume ACω. A connected triad with nonempty incoming boundary admits a presentation relative to that boundary with no 0-handles; when the incoming boundary is empty, exactly the 0-handles needed to create the components remain.

[F5]

Morse functions and handle decompositions correspond: Assume ACω. Every finite handle decomposition of a compact triad relative to its incoming face is induced by an adapted excellent Morse function with one critical point per handle, of the same index (and conversely).

[A1]

For k≥1 the attaching region Sk−1×Dn−k is nonempty: Sk−1≠∅ for k≥1, and Dn−k≠∅ for 0≤k≤n. For k=0 the attaching region is S−1×Dn=∅.

Verification

technique · direct
1.1F1A1givenalgebra

The initial stage of any presentation relative to M0=∅ is empty, so its boundary is empty as well, and the first attaching embedding h1 must map into it; hence the first handle must have empty attaching region. By [A1] this happens exactly for k=0: the attaching region of a 0-handle is S−1×Dn=∅, while a k-handle with k≥1 has nonempty attaching region and cannot be attached to the empty initial boundary. Therefore every presentation begins with at least one 0-handle.

2.1F2F4step 1.1algebra

A connected manifold with empty incoming boundary needs at least one 0-handle, since the first stage is empty and only a 0-handle creates a component by [F2]; and by [F4] exactly the 0-handles needed to create the components of W remain, which for connected W is one 0-handle. Hence the elimination of 0-handles is impossible when M0=∅, and the hypothesis M0≠∅ in [F4] is necessary.

3.1F3step 2.1construct

The sphere example: the closed n-sphere is the union of two closed disks glued along their common boundary sphere, Sn=Dn∪Sn−1Dn. Read the first disk as a 0-handle and the second as an n-handle attached along its whole boundary Sn−1, which by [F3] fills the whole boundary sphere and produces Sn. This presentation has exactly one 0-handle and one n-handle, and no other handles, in agreement with the fact that a connected manifold with M0=∅ keeps exactly one 0-handle by step 2.1 and that the n-handle closes the remaining boundary sphere.

4.1F3F5step 1.1step 3.1algebra∎

By [F5] the presentation of step 3.1 is realized by a Morse function on the triadic description of Sn with two critical points, of indices 0 and n; this is the standard round-sphere height function with a minimum and a maximum. In particular the sphere carries a presentation with exactly one 0-handle as claimed, and the presentation of any connected triad with empty incoming boundary must begin with a 0-handle, so the elimination proposition cannot be applied without change in that case.

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