Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Index zero handles create components

Statement

Assume ACω. A 0-handle on a smooth n-manifold with boundary attaches along the empty set and adds one disjoint n-disk component. This includes an empty starting manifold and n=0.

Facts & Assumptions

[F1]

Attaching a smooth handle with corner rounding: Assume ACω. Let X be a smooth n-manifold with boundary, and let k be an integer with 0kn. Attach the handle of def-k-handle-core-cocore-attaching-region-and-belt-sphere by a smooth embedding h:Sk1×DnkX that extends to a neighborhood of the disk factor. Form the quotient of X(Dk×Dnk) identifying z with h(z) in the attaching region. The disk coordinates trivialize the normal bundle of the attaching sphere; this framing is part of the data. Use collars from thm-collar-neighborhood-theorem to give the seam its product smooth charts, then round the compact codimension-two corner. A compatible rounding is a smooth monotone planar profile, transverse to a common diagonal direction, agreeing with the two faces away from a small corner neighborhood. In coordinates along that diagonal it is a graph. This convention fixes the gluing and collar data; changing the attaching embedding is a different question. There is no corner to round when k=0 or k=n.

Proof

Given: The objects and hypotheses in the statement.

1.1

At k=0 the handle is D0×DnDn and its attaching region is S1×Dn=. Thus the defining quotient makes no identifications between the old manifold and the disk.

F1algebra
2.1

The quotient is their disjoint union. The disk is connected and nonempty, so it supplies exactly one new component, including when the old manifold is empty. At n=0 the new disk is a single point. There is no corner seam to round.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources