Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Sublevels of height on the sphere

Example

Assume ACω. For height f(x)=xn+1 on Sn⊂Rn+1, n≥1, the sublevel is empty for a<−1, a point at a=−1, a closed n-disk for −1<a<1, and all of Sn for a≥1. The regular-sublevel changes use one 0-handle and one n-handle.

Facts & Assumptions

[F1]

One critical point handle attachment: Assume ACω. Let f:M→R be smooth on a boundaryless n-manifold and let a<b be regular values. If f−1([a,b]) is compact and has exactly one critical point p, nondegenerate of index k, then Mb is diffeomorphic to Ma with one k-handle attached and corners rounded. No orientation or Morse–Smale hypothesis is required.

[F2]

Index zero handles create components: A 0-handle on a smooth n-manifold with boundary attaches along the empty set and adds one disjoint n-disk component. This includes an empty starting manifold and n=0.

[F3]

Index n handles cap boundary spheres: An n-handle attaches along its whole Sn−1 boundary. For n≥2 it fills a boundary component diffeomorphic to Sn−1. For n=1 its attaching S0 is a pair of boundary points, possibly in different components. For n=0 it is the same disjoint point attachment as a 0-handle.

Verification

Given: The objects and hypotheses in the example.

1.1givenalgebra

A critical point has the vertical vector normal to the sphere, so the only critical points are the two poles. In horizontal coordinates z at those poles, height is respectively −1−∣z∣2 and 1−∣z∣2; their Hessians at zero are +I and −I. The indices are 0 and n, and their values are −1 and 1.

2.1step 1.1algebra

Stereographic coordinates from the north pole identify Sn∖{north} with Rn and give height (∣w∣2−1)/(∣w∣2+1). For −1<a<1 the sublevel is therefore ∣w∣2≤(1+a)/(1−a), a closed disk. The values at and beyond the poles give the point, empty set and whole sphere stated above.

3.1F1F2F3step 1.1∎

The sphere is compact, and each band crossing only one pole satisfies the handle theorem. The lower change adds a disjoint disk; the upper change caps its boundary by the whole-boundary attachment. At n=1 the cap attaches along two endpoints, as required by the endpoint qualification.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources