Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A context-specific expert class with no shared policy structure

Example

Let n≥1 be an integer, let C be a nonempty finite context set of size c, and let k>1 be an integer number of actions. Fix a context sequence c1,…,cn∈C and reward vectors xt∈[0,1]k for t∈[n], all before learner randomization. Take as experts every function ϕ:C→[k], with advice row E(t)ϕ,i=1{ϕ(ct)=i}. There are M=kc such experts and no constraint links the action assigned to one context to the action assigned to another. With learning rate η=2log⁡(kc)/(nk), Exp4's expected regret against this class is at most 2nkclog⁡k.

Example references

Contextual bandit protocol: expert advice rows and fixed oblivious context/reward sequences use this protocol.

Exp4 algorithm: each deterministic policy map supplies one advice row at the observed context.

Expected-regret theorem: the general finite-expert bound applies to the kc policy maps.

Natural-logarithm product law: log⁡(kc)=clog⁡k.

Facts & Assumptions

Given: n≥1, a finite nonempty context set C with ∣C∣=c, a fixed oblivious context sequence, fixed oblivious reward vectors xt∈[0,1]k for t∈[n], k>1, and the expert class of all maps ϕ:C→[k].

[F1]

Contextual bandit protocol with finite expert advice: the theorem applies to deterministic advice matrices fixed before learner randomization, with each expert row a probability vector.

[F2]

Exp4 expected regret against the best fixed expert: with M>1 experts, horizon n≥1, k>1, and its tuned learning rate, Rn≤2nklog⁡M.

[F3]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: for positive a,b, log⁡(ab)=log⁡a+log⁡b.

Verification

1.1F1givenconstructalgebra

For each map ϕ and each round t, exactly one indicator 1{ϕ(ct)=i} equals one, so its advice row is a probability vector. A map chooses one of k actions independently at each of the c contexts; therefore there are exactly M=kc experts. The fixed context sequence makes the resulting advice sequence oblivious.

2.1F2F3step 1.1algebra∎

Since c≥1 and k>1, M=kc>1, so [F2] applies and gives Rn≤2nklog⁡(kc). Repeated use of [F3] gives log⁡(kc)=clog⁡k, hence Rn≤2nkclog⁡k. This is a finite-sequence regret bound; it asserts no stochastic contextual generalization.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources