How statement and proof provenance work
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A two-state hidden Markov filter and smoother
Example
Let with counting measure. Take and transition matrix where rows index the current state. At each time let and , with the complementary probabilities for observation . For observations , the exact filter at time is on states , while the smoothing law of given both observations is . This finite model has positive evidence at both observed times.
Verification
Given: AC, the finite-horizon kernel model, and observations in the Example.
[A1] AC states that every family of nonempty sets has a choice function. The Axiom of Choice
[F1] Filtering and smoothing kernels are conditional laws given the stated observation histories. Filtering, predictive, and smoothing laws in a finite-horizon state-space model
[F2] For dominated observation kernels, the prediction and update are given by the exact recursion, with evidence computed by summing the likelihood against the predictive state law. Exact state-space filtering recursion under dominated observations
[F3] The finite-horizon model law is the ordered product of the initial, transition, and observation kernels. Finite-horizon state-space kernel law exists and is unique
[F4] Under AC the data-indexed conditional filtering and smoothing kernels exist for this finite standard-Borel model. Filtering and finite-horizon smoothing laws exist
[F5] The model supplies transition and observation probability kernels. General finite-horizon state-space models by kernels
[F6] The recursive filtering procedure uses the prediction/update formulas and predictive filler on zero or infinite evidence. Recursive Bayesian filtering under dominated observations
Let for . Counting measure integrates by finite sums, so and ; every function on these finite discrete spaces is product-measurable. Thus [F2] applies. Since is uniform and each transition-matrix column sums to one, is uniform; hence , and Bayes' finite sum gives and .
Predicting through gives and .
The evidence for is ; thus and , which sum to one.
By the ordered path law [F3], for the conditional probability of given is ; the factor cancels in this conditional probability because it depends only on the fixed state and event . These sums are for and for . Multiplying by the time-1 filter gives conditional smoothing masses ; their sum is , the conditional evidence in step 3.1, so the smoothing law of is . The history event has positive probability by step 1.1 and step 3.1, so its conditional distribution is fixed by the event identities.
Depends on
- The Axiom of Choice
- Filtering, predictive, and smoothing laws in a finite-horizon state-space model
- Recursive Bayesian filtering under dominated observations
- Filtering and finite-horizon smoothing laws exist
- Exact state-space filtering recursion under dominated observations
- General finite-horizon state-space models by kernels
- Finite-horizon state-space kernel law exists and is unique
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Simo Särkkä and Lennart Svensson, Bayesian Filtering and Smoothing, 2nd ed., Chapter 6 (standard reference, not scraped)
- Arnaud Doucet and Adam M. Johansen, A Tutorial on Particle Filtering and Smoothing: Fifteen Years Later, §2.1 (standard reference, not scraped)