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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A two-state hidden Markov filter and smoother

Example

Let E0=E1=E2=F1=F2={0,1} with counting measure. Take μ0=(1/2,1/2) and transition matrix M=(3/41/41/43/4), where rows index the current state. At each time let Gt(1∣0)=1/4 and Gt(1∣1)=3/4, with the complementary probabilities for observation 0. For observations Y1=1,Y2=0, the exact filter at time 2 is (9/14,5/14) on states (0,1), while the smoothing law of X1 given both observations is (5/14,9/14). This finite model has positive evidence at both observed times.

Verification

Given: AC, the finite-horizon kernel model, and observations in the Example.

[A1] AC states that every family of nonempty sets has a choice function. The Axiom of Choice

[F1] Filtering and smoothing kernels are conditional laws given the stated observation histories. Filtering, predictive, and smoothing laws in a finite-horizon state-space model

[F2] For dominated observation kernels, the prediction and update are given by the exact recursion, with evidence computed by summing the likelihood against the predictive state law. Exact state-space filtering recursion under dominated observations

[F3] The finite-horizon model law is the ordered product of the initial, transition, and observation kernels. Finite-horizon state-space kernel law exists and is unique

[F4] Under AC the data-indexed conditional filtering and smoothing kernels exist for this finite standard-Borel model. Filtering and finite-horizon smoothing laws exist

[F5] The model supplies transition and observation probability kernels. General finite-horizon state-space models by kernels

[F6] The recursive filtering procedure uses the prediction/update formulas and predictive filler on zero or infinite evidence. Recursive Bayesian filtering under dominated observations

1.1A1givenF2F3F5F6algebra

Let gt(i,j):=Gt(i,{j}) for i,j∈{0,1}. Counting measure integrates by finite sums, so ∑jgt(i,j)=Gt(i,{0,1})=1 and Gt(i,C)=∑j∈Cgt(i,j); every function on these finite discrete spaces is product-measurable. Thus [F2] applies. Since μ0 is uniform and each transition-matrix column sums to one, X1 is uniform; hence P(Y1=1)=12(14+34)=12, and Bayes' finite sum gives P(X1=0∣Y1=1)=(1/2)(1/4)1/2=1/4 and P(X1=1∣Y1=1)=3/4.

2.1A1givenF2F6step 1.1algebra

Predicting through M gives P(X2=0∣Y1=1)=1434+3414=38 and P(X2=1∣Y1=1)=1414+3434=58.

3.1A1givenF2F6step 2.1algebra

The evidence for Y2=0 is (3/8)(3/4)+(5/8)(1/4)=7/16; thus P(X2=0∣Y1=1,Y2=0)=9/14 and P(X2=1∣Y1=1,Y2=0)=5/14, which sum to one.

4.1A1givenF1F3F4step 1.1step 3.1algebra∎

By the ordered path law [F3], for i=0,1 the conditional probability of Y2=0 given X1=i,Y1=1 is ∑j=01MijG2(j,{0}); the factor G1(i,{1}) cancels in this conditional probability because it depends only on the fixed state i and event Y1=1. These sums are (3/4)(3/4)+(1/4)(1/4)=5/8 for i=0 and (1/4)(3/4)+(3/4)(1/4)=3/8 for i=1. Multiplying by the time-1 filter (1/4,3/4) gives conditional smoothing masses (5/32,9/32); their sum is 7/16, the conditional evidence in step 3.1, so the smoothing law of X1 is (5/14,9/14). The history event has positive probability by step 1.1 and step 3.1, so its conditional distribution is fixed by the event identities.

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