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A finite-matrix Schrödinger split preserves norm

Example

Realify C2 as R4 and let HK=(0001),V=(0110),A=−iHK,B=−iV. Here HK is a two-level kinetic matrix and V is a Hermitian potential coupling. The finite-dimensional Schrödinger equation is ψ′=(A+B)ψ=−i(HK+V)ψ. Each exact kinetic or potential subflow preserves the Euclidean norm, so every exact Lie or Strang composition does as well. The local errors are nonzero for suitable initial data because the two generators do not commute; no spatial PDE or unbounded-operator conclusion is claimed.

Facts & Assumptions

Given: The matrices HK,V,A,B and a differentiable solution ψ(t)∈C2 of the total or split Schrödinger equation.

[F1]

Lie and Strang compositions of exact split flows: Lie and Strang maps are compositions of the exact flows of the two component fields, and their bracket is [a,b]=Db a−Da b.

[F2]

Lie and Strang splitting errors have commutator expansions: the leading Lie defect is 12h2[a,b], and the Strang defect has the stated cubic double-bracket coefficient.

[F5]

Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes: matrix products have their standard associative coordinate meaning.

[F7]

The exponential series of a bounded operator: a finite matrix exponential is defined for every real time, equals I at zero, and has derivative AetA.

[A1]

HK∗=HK and V∗=V, as direct conjugate-transpose calculation verifies.

Proof

1.1A1F3F4F5F6F7algebra

Let H be any of HK, V, or HK+V. Its exact flow exists for all real time by [F7], and every solution obeys ψ′=−iHψ. By [F3]–[F6], differentiating the real function ψ∗ψ gives ddt(ψ∗ψ)=(ψ′)∗ψ+ψ∗ψ′=iψ∗H∗ψ−iψ∗Hψ=0, where [A1] supplies H∗=H. Therefore [F6] makes ∥ψ(t)∥22 constant on every admitted interval, and each exact subflow and the total flow preserve norm.

1.2A1F1F5algebra

Direct multiplication gives C:=BA−AB=HKV−VHK=(0−110)≠0. This is the linear matrix of [a,b] by [F1]. Also CA−AC=i(0110),CB−BC=2i(100−1).

2.1F1step 1.1

By [F1], a Lie or Strang step is a composition of exact component flows. Each factor preserves norm by step 1.1, so the composition preserves norm by repeated application of the same equality.

3.1F2step 1.2algebra∎

For ψ=e1, the Lie coefficient 12Cψ is nonzero. The Strang coefficient −124(CA−AC)ψ−112(CB−BC)ψ is also nonzero, since its first coordinate is −i/6. Applying [F2] shows the exact subflows retain norm while the Lie and Strang maps have their respective nonzero local splitting defects.

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