Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Gaussian integrand: exact Monte Carlo moments and asymptotic error

Example

Assume AC and let X have law N(μ,σ2) with σ>0. Use the identity integrand g(x)=x, whose target is E[g(X)]=μ, and take IID outputs (Yi)i≥1 with this law. Then E[Yˉn]=μ and Var⁡(Yˉn)=σ2/n; the estimated standard error is relatively consistent, and n(Yˉn−μ)⇒N(0,σ2).

Facts & Assumptions

Given: AC, σ>0, and a real IID sequence (Yi)i≥1 with common law N(μ,σ2).

[A1]

The Axiom of Choice: AC is the axiom that every family of nonempty sets has a choice function.

[F1]

Location-scale normal laws have their stated mean and variance: Under AC, a real random variable with law N(m,σ2) for σ≥0 has mean m and variance σ2.

[F2]

Unbiasedness and exact variance of the IID Monte Carlo mean: For integrable IID outputs, E[Yˉn]=μ; with a finite second moment, Var⁡(Yˉn)=σ2/n.

[F3]

Consistency of the IID Monte Carlo sample variance: With finite second moment, sn2→σ2 almost surely, and for σ2>0, se^n/(σ/n)→1 almost surely.

[F4]

Lindeberg–Lévy limit for the IID Monte Carlo mean: Under AC and 0<σ2<∞, n(Yˉn−μ)⇒N(0,σ2).

[F5]

IID Monte Carlo sample mean, variance, and standard error: se^n=sn/n for n≥2 under the finite-second-moment contract.

Verification

1.1A1F1F2given

By [F1], each output has mean μ and variance σ2, so its first absolute moment and second moment are finite. Applying [F2] gives E[Yˉn]=μ and Var⁡(Yˉn)=σ2/n.

1.2A1F1F3F5given

The finite-second-moment hypotheses of [F3] hold by [A1] and [F1]. Thus sn2→σ2 almost surely and, using the plug-in definition [F5], se^n/(σ/n)→1.

2.1A1F1F4given∎

The sequence has positive finite variance and AC is assumed, so [F4] applies and gives n(Yˉn−μ)⇒N(0,σ2).

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources