Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Gram–Schmidt on an explicit basis of C2 with conjugation visible

Example

For the linear-first standard inner product on C2, Gram–Schmidt applied to v0=(1,i) and v1=(1,1) produces

e0=(1,i)2,e1=(1+i2,1i2).

Facts & Assumptions

Given: The vectors v0=(1,i) and v1=(1,1) in C2.

[L2]

Gram–Schmidt uses the coefficient vk,ej under the linear-first convention (Gram–Schmidt turns every finite independent list into an orthonormal list with the same successive spans).

Verification

technique · computation
1.1

From [L1], v0=2, so e0=v0/2. The projection coefficient is v1,e0=(1i)/2.

L1L2L3
2.1

Subtraction gives u1=v1v1,e0e0=((1+i)/2,(1i)/2). By [L3], u12=1, so e1=u1.

step 1.1L1L3algebra
3.1

Direct use of [L1] gives e1,e0=0 and, by conjugate symmetry, e0,e1=0. Both vectors have norm one, so the displayed list is orthonormal.

step 1.1step 2.1L1L3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 53 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.