Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Three left vertices with only two collective neighbours fail Hall's condition and cannot all be matched

Example

Take left part X={x1,x2,x3}X=\{x_1,x_2,x_3\}, right part Y={a,b}Y=\{a,b\}, and all six possible edges between the two parts. This graph has no matching saturating XX.

Facts & Assumptions

Given: The displayed finite bipartite graph.

[L1]

A finite bipartite graph has a matching saturating its left part exactly when Hall's condition holds (Hall's marriage theorem for a finite bipartite graph).

Verification

Verification technique: direct.

1.1

For S=XS=X, the neighbourhood is N(S)={a,b}N(S)=\{a,b\}, so N(S)=2<3=S|N(S)|=2<3=|S|.

given
1.2

Thus Hall's condition fails, and [L1] proves that no matching can saturate all three left vertices.

L1
2.1

The two available right vertices also show directly that any matching has at most two edges.

step 1.1step 1.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 21 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.