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ExampleConstruction: Literature-sourcedVerification: Literature-sourcedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Hook lengths for one-row, one-column and hook shapes

Example

For n≥1, under the hook length formula: (i) for λ=(n) the hooks are h(1,j)=n−j+1 (1≤j≤n), the product is n!, and f(n)=1; (ii) for λ=(1n) the hooks are again 1,2,…,n, the product is n!, and f(1n)=1; (iii) for n≥2 and λ=(n−1,1) the hooks are h(1,1)=n, h(1,j)=n−j for 2≤j≤n−1, and h(2,1)=1, so the product is n(n−2)! and f(n−1,1)=n!/(n(n−2)!)=n−1. For n=1 the shape (0,1) is not a partition; the smallest member of this hook-shape family is (1,1) for n=2, where f(1,1)=1 agrees with n−1=1 computed in the one-column case.

Facts & Assumptions

Given: Integers n≥1 and the partitions (n), (1n) and, for n≥2, (n−1,1) of n, with their Young diagrams and conjugates.

[F1]

h(i,j)=λi−j+λj′−i+1 for (i,j)∈[λ] and P(λ)=∏h; in particular h(1,j)=λ1−j+λj′ and h(i,1)=λi−1+λ1′−i+1 (Hook, arm, leg, and hook length of a box).

[F2]

fλ=n!/P(λ) for λ⊢n≥1, so fλ is determined by the multiset of hook lengths (The hook length formula).

Verification

technique · direct
1.1F1F2algebra

(One row.) For λ=(n) one has λj′=1 for 1≤j≤n, so h(1,j)=n−j+1−1+1=n−j+1, the hooks are n,n−1,…,1, the product is n!, and [F2] gives f(n)=n!/n!=1; this includes n=1 with the single hook h(1,1)=1.

1.2F1F2algebra

(One column.) For λ=(1n) one has λ1′=n and λj′=0 for j≥2, so h(i,1)=1−1+n−i+1=n−i+1 for 1≤i≤n and there are no other boxes; the hooks are again n,n−1,…,1, the product is n!, and [F2] gives f(1n)=1.

1.3F1givenalgebra

(Hook shape, n≥3.) For λ=(n−1,1) the conjugate is λ′=(2,1,…,1) with λ1′=2 and λj′=1 for 2≤j≤n−1: h(1,1)=(n−1)−1+2−1+1=n; for 2≤j≤n−1, h(1,j)=(n−1)−j+1−1+1=n−j, giving the values n−2,n−3,…,1; and h(2,1)=1−1+2−2+1=1.

2.1F2step 1.3algebra

(Hook shape, product and count.) The product of the hooks of step 1.3 is n⋅(n−2)!⋅1=n(n−2)! (the factors n−2,…,1 contribute (n−2)!); hence [F2] gives f(n−1,1)=n!/(n(n−2)!)=(n−1)!/(n−2)!=n−1.

3.1step 1.2step 1.3step 2.1algebra

(The case n=2.) Here (n−1,1)=(1,1)=(12) is the one-column shape of step 1.2: the formula of step 2.1 reads n(n−2)!=2⋅0!=2, the hook product is indeed 2, and f(1,1)=1=n−1; the intermediate range 2≤j≤n−1 is empty and contributes the empty product 1.

4.1F1step 1.1step 1.2given∎

(Endpoint n=1.) The shape (n−1,1)=(0,1) is not a partition, so the hook-shape family begins at n=2; for n=1 the only partitions are (1)=(11), covered by steps 1.1 and 1.2 with f(1)=1.

Depends on

Used by

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Sources