Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Hopf line bundle over S² by clutching

Example

Identify S2 with CP1. With the upper-to-lower coefficient convention fixed on the A page, the map

g:S1GL1(C),g(z)=z,

clutches the tautological Hopf line γ. Interchanging the two disk charts changes the transition to z1 and gives the dual line γ.

Facts & Assumptions

Given: CP1, split into the two affine closed disks along z=1.

[F1]

The clutching relation sends a plus-chart coefficient v to the minus-chart coefficient g(z)v; swapping charts inverts g (Clutching construction for bundles over a suspension).

[F2]

The tautological line has fiber the represented line in C2 (Tautological lines over projective spaces).

Verification

technique · direct
1.1

On the plus disk use points [z:1], z1, and the tautological frame s+(z)=(z,1). On the minus disk use [1:w], w1, with w=z1 on the equator, and frame s(w)=(1,w). These vectors span the represented lines by [F2].

F2construct
2.1

For z=1, one has s+(z)=(z,1)=z(1,z1)=zs(z1). Thus a physical vector with plus coefficient v has minus coefficient zv. By [F1], the clutching function is exactly g(z)=z, not its inverse.

F1step 1.1algebra
3.1

Interchanging the plus and minus charts reverses the coordinate change, so [F1] gives g1(z)=z1. Dualizing a line bundle inverts its scalar transition functions, hence this second clutching is γ. This completes the sign calculation without a choice principle.

F1step 2.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources