Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An incomplete finite trial space can lie strictly above the Hamiltonian ground energy

Example

Let the finite configuration space be C2 and the Hermitian Hamiltonian be H=diag⁡(0,2). Its ground energy is 0, while the one-dimensional trial space Vtrial=span⁡{e2} has variational energy 2. This is the finite-dimensional form of the warning that an incomplete configuration-interaction space need not contain the ground state.

Facts & Assumptions

Given: The Hamiltonian H=diag⁡(0,2) on C2 and trial space span⁡{e2}.

Verification

1.1F1givenalgebra

The eigenvalues of H are 0 and 2, with corresponding unit eigenvectors e1,e2 by [F1]. For a unit vector v=(a,b), v∗Hv=2∣b∣2≥0, and equality holds at e1, so the full-space ground energy is 0.

2.1step 1.1givenalgebra∎

Every unit vector in Vtrial is eiθe2 for some real θ, and its energy is (eiθe2)∗H(eiθe2)=2. Thus the restricted minimum is 2>0, strictly above the full finite-dimensional ground energy.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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