Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passverified 2026-08-03 (gpt-5.6-sol-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

[G:G]=1[G:G]=1 and, for finite GG, [G:{e}]=G[G:\{e\}]=|G|

Example

For every group GG, [G:G]=1[G:G]=1. If GG is finite with identity ee, then [G:{e}]=G[G:\{e\}]=|G|.

Facts & Assumptions

Given: A group GG with identity ee; for the second assertion, assume GG is finite.

[F1]

The cosets are gH={gh:hH}gH=\{gh:h\in H\}, and the index is the cardinality of the coset set when finite (Left and right cosets gHgH and HgHg of a subgroup, The coset set G/HG/H and the index [G:H][G:H] of a subgroup).

Verification

technique · direct
1.1

For H=GH=G, every coset gGgG equals GG, so the coset set is {G}\{G\} and [G:G]=1[G:G]=1.

F1
1.2

The set H={e}H=\{e\} is a subgroup: it contains ee, while ee=eee=e and e1=ee^{-1}=e give closure under products and inverses by [L2]. Every coset is the singleton g{e}={g}g\{e\}=\{g\}; equivalently, [L1] gives G=[G:{e}]1|G|=[G:\{e\}]\cdot1. Hence [G:{e}]=G[G:\{e\}]=|G|.

F1L1L2
2.1

Steps 1.1 and 1.2 establish the two index formulas.

step 1.1step 1.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

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Sources