Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Partition weights in two overlapping charts

Example

Let f∈Cc∞((−1,1)). Use the increasing charts x and y=2x on overlapping domains containing its support. For smooth weights ρ,1−ρ with 0≤ρ≤1 on a neighborhood of the support, the two weighted chart integrals sum to ∫f(x)dx, independently of ρ.

Facts & Assumptions

[F1]

Independence of atlas, partition and refinement: The compact-support integral on an oriented manifold is independent of the chart cover, coordinate maps, subordinate partition, and refinement. If U⊂M is open and contains supp⁡ω, with its restricted orientation, then ∫Uω∣U=∫Mω.

[F2]

Chart integral with its orientation sign: Let Mn be oriented and ω a smooth top form with compact support contained in a connected chart (U,ϕ). For n≥1 write (ϕ−1)∗ω=f dx1∧⋯∧dxn. Let σϕ∈{1,−1} be the sign of its coordinate frame relative to the chosen orientation. Define the chart integral by Iϕ(ω)=σϕ∫Rnf~(x) dx. Here f~ is the Riemann-integrable zero extension, including across a genuine half-space face, as in lem-chart-supported-coefficients-have-well-defined-riemann-integrable-half-space-extensions. For n=0, a connected chart is a point p, and set Ip(ω)=ε(p)ω(p) using its determinant-line sign. Empty support gives zero. Negative charts are allowed: the upper-half-line chart u=b−t at the right endpoint of an increasing interval has sign −1.

Verification

Given: The objects and hypotheses in the statement above.

1.1F2algebra

The x-chart coefficient of the first term is ρ(x)f(x). Since dx=dy/2, the y-chart coefficient of the second is (1−ρ(y/2))f(y/2)/2. Both have compact support; weights outside the support do not affect the products. The chart definition gives their ordinary Riemann integrals.

2.1F1step 1.1∎

Substitute y=2x in the second integral and add: ∫ρf dx+∫(1−ρ)f dx=∫f dx. This is the finite product-partition identity underlying global independence. It includes f=0 and weights identically zero or one; no unweighted overlap is counted twice.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources