Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The zero-noise boundary of truncated risk

Example

Assume Countable Choice for the upstream sequence-model coordinates. Take ϵ=0 and Q>0. In the zero-noise sequence model, Zj=θj exactly, so the cutoff error is the deterministic squared tail ∑j>Dθj2. For weights aj=jr with r>0, its worst case over Θa(Q) is Q2/(D+1)2r and tends to 0 as D→∞. For the equally weighted ellipsoid aj=1, the worst case is Q2 for every finite D, attained by θ=QeD+1. This is a deterministic boundary of the sequence-risk formula; it makes no claim about arbitrary bounded perturbations of the original inverse data.

Facts & Assumptions

[A1]

The Axiom of Countable Choice (ACω): Countable Choice is used upstream to choose the compact SVD coordinates and identify the complete-basis coefficient space.

[F1]

Gaussian sequence inverse model: At ϵ=0, Zj=θj deterministically.

[F2]

Weighted ellipsoid class for sequence inversion: For any positive nondecreasing weights, Θa(Q) is defined by ∑jaj2θj2≤Q2.

[F3]

Exact worst-case risk of the truncated estimator: The zero-noise worst-case squared error is Q2/aD+12, attained by a truth supported only at coordinate D+1.

Given: Countable Choice, Q>0, a finite cutoff D∈N0, and either weights aj=jr with r>0 or aj=1 for all j.

Verification

1.1A1F1F2F3algebra

Under [A1], the sequence model coordinates are fixed. Using [F1] and substituting ϵ=0 and aD+1=(D+1)r in [F3] gives Q2/(D+1)2r; since r>0, this tends to 0 as D→∞.

2.1A1F2F3algebraconstruct∎

Under [A1], [F3] applies to the unit-weight ellipsoid. The ellipsoid condition in [F2] is ∥θ∥22≤Q2, so the squared tail is at most Q2. The vector θ=QeD+1 belongs to the ellipsoid and its entire squared norm lies beyond D, so it attains Q2. This is also the ϵ=0, aD+1=1 case of [F3].

Depends on

Used by

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