Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Lebesgue measure of an interval, of a box, of Q and of the irrationals in [0,1]

Example

Assume the Axiom of Countable Choice. Then every bounded interval in R has Lebesgue measure equal to its length, every box in Rn has Lebesgue measure equal to the product of its side lengths, λ1(Q)=0, and

λ1([0,1]Q)=1.

In particular a degenerate interval and the empty box both have measure 0.

Facts & Assumptions

Given: The Axiom of Countable Choice.

[L1]

Assuming countable choice, a box in Rn with parameters aibi is Lebesgue measurable of measure i<n(biai) (A box in Rn with parameters aibi is Lebesgue measurable of measure i<n(biai), whichever of its faces are included).

[L2]

Every at most countable subset of Rn is Lebesgue null; in particular λ1(Q)=0 (Every at most countable subset of Rn is Lebesgue null; in particular λ1(Q)=0).

Verification

technique · direct
1.1

By [L1], every interval with endpoints ab and every box with real side parameters has Lebesgue measure equal to its geometric length or volume, whatever choice of open and closed faces is made.

L1
1.2

The rationals form a Lebesgue null subset of R, so λ1(Q)=0.

L2
2.1

Since [0,1]=(Q[0,1])([0,1]Q) and λ1([0,1])=1 by step 1.1, step 1.2 and [L3] give λ1([0,1]Q)=1.

step 1.1step 1.2L3algebra
3.1

Step 1.1 also covers the boundary cases: if a=b then the interval has measure 0, and the empty box has measure 0.

step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources