Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Lebesgue measure of an interval, of a box, of Q and of the irrationals in [0,1]

Example

Assume the Axiom of Countable Choice. Then every bounded interval in R has Lebesgue measure equal to its length, every box in Rn has Lebesgue measure equal to the product of its side lengths, λ1(Q)=0, and

λ1([0,1]∖Q)=1.

In particular a degenerate interval and the empty box both have measure 0.

Facts & Assumptions

Given: The Axiom of Countable Choice.

[L1]

Assuming countable choice, a box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai) (A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included).

[L2]

Every at most countable subset of Rn is Lebesgue null; in particular λ1(Q)=0 (Every at most countable subset of Rn is Lebesgue null; in particular λ1(Q)=0).

Verification

technique · direct
1.1L1

By [L1], every interval with endpoints a≤b and every box with real side parameters has Lebesgue measure equal to its geometric length or volume, whatever choice of open and closed faces is made.

1.2L2

The rationals form a Lebesgue null subset of R, so λ1(Q)=0.

2.1step 1.1step 1.2L3algebra

Since [0,1]=(Q∩[0,1])⊔([0,1]∖Q) and λ1([0,1])=1 by step 1.1, step 1.2 and [L3] give λ1([0,1]∖Q)=1.

3.1step 1.1∎

Step 1.1 also covers the boundary cases: if a=b then the interval has measure 0, and the empty box has measure 0.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources