Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

LIL rules out a square-root-time bound

Example

Let B be a standard Brownian motion. Almost surely there is no finite random constant C and no random δ>0 such that BtCtfor all 0<t<δ. Thus the square-root bound that holds in expectation for a single time is false as a pathwise statement near the origin.

Facts & Assumptions

Given: AC and a standard Brownian motion B.

[F1]

Almost surely lim supt0Bt/2tloglog(1/t)=1 and the corresponding limit inferior is 1. Brownian law of the iterated logarithm at zero

[F2]

AC is assumed explicitly in this example. The Axiom of Choice

Verification

technique · direct
1.1

On the probability-one event of [F1], combining the two limit statements gives lim supt0Bt/2tloglog(1/t)=1, so there are tn0 with 2loglog(1/tn)Btn/2tnloglog(1/tn).

givenF1
2.1

For such a sequence Btn/tn=2loglog(1/tn)Btn2tnloglog(1/tn); hence for every finite constant c there exist t(0,δ) with Bt>ct, whatever δ>0 is prescribed, which is exactly the failure of the displayed bound for a finite random C and random δ>0.

step 1.1
3.1

The cases are covered: only t>0 is quantified, so the normalizer loglog(1/t) is defined and positive for small t; the constant C is allowed to be random and finite, and the argument produces, on the given outcome, arbitrarily small times violating any fixed finite value; and AC enters only through [F2].

step 2.1F2given

Source notes

The law of the iterated logarithm at zero does more than fail to provide a one-half modulus: it exhibits a sequence of times along which Bt/t diverges. Durrett's Theorem 8.5.1, transported to zero, is the source of that sequence.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources