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A periodic manufactured solution for the diagonal-diffusion HJB stencil

Statement

For d=1, one control, α=1, and b=0 on T1, set u(x,t)=e−tcos⁡(2πx),f(x,t)=(−1+4π2)e−tcos⁡(2πx). Then ut−(uxx+f)=0 exactly. On a periodic grid h=1/N, the centered diffusion scheme with 0<τ≤h2/2 satisfies a normalized one-step residual of order O(τ+h2) on the sampled exact solution. This is a local residual calculation, not a global solution-error estimate.

Facts & Assumptions

Given: The smooth periodic function and forcing in the statement and the one-control explicit scheme of Explicit monotone diagonal-diffusion Bellman grid update.

[F1]

The continuous operator in one dimension is ut−(αuxx+bux+f)=0 (Periodic diagonal controlled-diffusion HJB Cauchy problem).

[F2]

Under b=0 and α=1, the normalized scheme residual equals the time difference quotient minus Dxxhu+f; its second-difference error on smooth tests is controlled by Smooth consistency of the diagonal-diffusion Bellman stencil.

Proof

1.1F1givenalgebra

Direct differentiation gives ut=−u and uxx=−4π2u. Therefore ut−uxx=(−1+4π2)u=f, proving the exact PDE identity in [F1]. The diffusion-dominance condition is automatic since b=0; the CFL condition is 2τ/h2≤1, which is exactly the stated time-step bound.

2.1F2step 1.1algebra∎

The discrete second difference is Dxxhu(xi,tn)=−4sin⁡2(πh)h2u(xi,tn). Taylor expansion in time gives (u(xi,tn+τ)−u(xi,tn))/τ=ut(xi,tn)+O(τ), while uxx−Dxxhu=(4sin⁡2(πh)h2−4π2)u=O(h2), because sin⁡z=z+O(z3) at z=0. Thus the exact normalized residual is O(τ+h2), agreeing with [F2]. No accumulated error is claimed.

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