How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Normalized Haar measure on a torus
Example
Assume the Axiom of Choice and let be an integer. Put and let be the quotient map. For nonnegative Borel , or Haar-integrable complex Borel , normalized Haar integration is For the cube and torus are singletons, and the right side uses mass one on the singleton (the empty product convention).
Facts & Assumptions
Given: A nonnegative integer , , , and .
AC is assumed (The Axiom of Choice); it covers the countable-choice measure suppliers and Haar existence and uniqueness.
A compact Hausdorff group has a unique left Haar probability measure, which is also right and inversion invariant (Normalized Haar probability on a compact group). This is the normalized measure on a compact Lie group (Normalized Haar measure on a compact Lie group). A left Haar measure is a nonzero left-invariant Borel measure, compact finite, outer regular on Borel sets and inner regular on open sets (Left Haar integral and left Haar measure).
For , Lebesgue measure is translation invariant, and its value on the half-open cube is its volume (Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation, Assuming countable choice, Lebesgue outer measure is an outer measure that restricts to elementary volume, Lebesgue measurable sets, the family , and the restricted set function ).
For , Lebesgue measure is Radon and compact-inner regular on every Borel set (Lebesgue measure is a Radon measure on R^n).
Verification
If , both spaces are singletons, their probability measure is Dirac, all translations and inversion are identity, and the asserted integral is evaluation at the point. Now suppose . Every coset modulo has a unique representative in , by subtracting the coordinatewise integer floors. Define for Borel . The preimage is Borel and countable disjoint unions pull back to disjoint unions, so this is a Borel measure; [L2] gives .
Let and . Partition into the Borel sets , . Only finitely many are nonempty, since and is fixed. Unique representatives imply that the translates are pairwise disjoint and their union is exactly : surjectivity follows by subtracting , and injectivity follows because two points of differing by an integer vector coincide. Translation invariance and finite additivity give . Half-open faces cause no overlap or omitted boundary points.
To prove regularity, let be Borel and . By [L3], for each there is compact with . Then is compact in , and . Applying this to gives a compact with ; the open set contains and its excess over has measure less than . Thus is both inner and outer regular.
The probability measure is compact finite and nonzero by step 1.1, left invariant by step 2.1, and regular by step 2.2. It is therefore a left Haar probability in the exact sense of [L1]. Apply the unique-left-Haar-probability clause of [L1]; it equals normalized Haar measure and in particular is also inversion invariant. We do not invoke uniqueness restricted to measures already known to be inversion invariant.
The integral formula holds for indicators of Borel sets by the definition of in step 1.1 and its identification in step 3.1. Finite linearity gives it for nonnegative simple functions. Increasing simple approximations, or equivalently the defining supremum for the nonnegative integral, give it for nonnegative Borel . Applying this to the positive and negative parts of the real and imaginary parts proves the formula for integrable complex ; applying it first to verifies integrability on the cube. The singleton case was established separately in step 1.1.
Depends on
- Normalized Haar probability on a compact group
- Left Haar integral and left Haar measure
- Assuming countable choice, Lebesgue outer measure is an outer measure that restricts to elementary volume
- Normalized Haar measure on a compact Lie group
- The Axiom of Choice
- Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- Lebesgue measure is a Radon measure on R^n
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
37 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Anthony W. Knapp, Lie Groups Beyond an Introduction, 2nd ed. (standard reference, not scraped)