Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Full action support permits reweighting while missing support does not

Example

Assume AC and take horizon H=1, discount γ=12, states s0,z, actions a,b at s0, and action c at z. Every action moves to z; action a gives reward 0, action b gives reward 1, and action c gives reward 0. The target policy chooses b at s0, and both policies choose c at z. With behavior probabilities μ(a∣s0)=μ(b∣s0)=12, full trajectory coverage holds: the single-trajectory ordinary importance-sampling score is 2 when action b is observed and 0 when action a is observed, and its expectation is the target value 1. If instead μ(a∣s0)=1, the target action has no behavior support. Two processes that agree on the logged action a and its reward 0, but give action b rewards 1 and −1, respectively, have identical logged-data laws and different target values; the behavior data cannot identify which value is correct.

Facts & Assumptions

Given: AC, the horizon-one MDP and policies in the Example, one behavior trajectory at a time, and the corresponding target value.

[F1]

Finite-horizon offline reinforcement-learning dataset and coverage: PHσ is the finite-horizon path law and the target value is the expectation of the discounted return.

[F2]

Ordinary, per-decision, and weighted trajectory importance sampling: for H=1, the ordinary score is the observed return multiplied by π(A0∣s0)/μ(A0∣s0).

[F3]

Without trajectory coverage, logged data need not identify policy value: two behavior-indistinguishable finite MDPs can have different target values when the target action is absent from behavior support.

Verification

1.1givenF1F2algebra

Under μ(b∣s0)=12, the ratio for an observed b is 1/(12)=2; its return is 1. The ratio for an observed a is 0/(12)=0; its return is 0. Thus the OIS score is 2 with probability 12 and 0 with probability 12, so its expectation is 1, equal to the target value. Since H=1, PDIS has the same score.

2.1givenF1F3algebra∎

Under μ(a∣s0)=1, the target trajectory taking b has target probability 1 and behavior probability 0, so the full-coverage premise fails and its likelihood ratio is undefined. The two reward choices r(b)=1 and r(b)=−1 yield the same deterministic logged trajectory but target values 1 and −1.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources