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A compactly supported velocity datum produces an expanding interval

Example

Let c>0, a>0, u0=0 and u1=1[−a,a]. Although this indicator is not in the classical data class of d'Alembert's formula and uniqueness in one dimension, its displayed integral expression extends directly to this bounded datum and gives u(x,t)=12c ∣[x−ct,x+ct]∩[−a,a]∣,t≥0, i.e. the length over 2c of the overlap of the moving interval with the data interval. For t>0 the nonzero set is exactly {x:∣x∣<a+ct} and its topological support is the closed interval [−a−ct,a+ct]; at t=0 the profile is identically zero and its support is empty. Once ct≥a, the profile equals a/c throughout {∣x∣≤ct−a}; the two wavefronts travel outward at speed c and the disturbance never reaches ∣x∣>a+ct.

Facts & Assumptions

Given: a speed c>0, a half-width a>0, the data u0=0, u1=1[−a,a], and the displayed function u.

[F1]

For admissible data, the d'Alembert expression is the unique classical solution (d'Alembert's formula and uniqueness in one dimension); its velocity integral is well defined for the bounded compactly supported indicator used here as well.

Verification

1.1F1algebra

Substituting u0=0 into the velocity integral gives u(x,t)=12c∫x−ctx+ct1[−a,a](y) dy=12c∣[x−ct,x+ct]∩[−a,a]∣, since the integral of the indicator is the overlap length. For smooth admissible approximations, the same d'Alembert expression is a classical solution by [F1].

1.2algebra

Nonzero set and plateau. For t>0, the overlap has positive length exactly when x−ct<a and x+ct>−a, that is ∣x∣<a+ct; its closure, the topological support, is [−a−ct,a+ct]. At t=0 the moving interval is a singleton, so the overlap has length zero for every x and the support is empty. The overlap is the full data interval, of length 2a, when ∣x∣≤ct−a (which requires ct≥a), giving value a/c there.

2.1algebra∎

The formula therefore has expanding nonzero set (−a−ct,a+ct) for t>0, closed support [−a−ct,a+ct], zero support at t=0, and the stated full-data plateau when ct≥a.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources