Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The two-vertex deterministic swap has absolute gap zero

Example

Let X={0,1} and let

P=(0110),π=(1/2,1/2).

The chain alternates deterministically between the two states. The absolute spectral gap is defined by Absolute spectral gap of a finite reversible chain on the mean-zero subspace.

Facts & Assumptions

Given: The finite reversible chain above, the period convention Period of a state, and the absolute-gap convention Absolute spectral gap of a finite reversible chain.

[F1]

Finite reversible Markov chain with positive stationary law: a reversible chain has a positive stationary law satisfying row-stationarity and detailed balance.

[F2]

Period of a state: the period is the gcd of the positive return times with positive transition probability.

[F3]

Absolute spectral gap of a finite reversible chain: δabs(P)=1−∥P∣H0∥2,π.

Verification

1.1F1givenalgebra

Both rows of P sum to one, πP=π, and π0P01=π1P10=1/2; the diagonal detailed-balance equations are automatic. Hence (X,P,π) is a finite reversible chain.

1.2F2givenalgebra

Starting from either state, a return occurs exactly at positive even times, so the return-time set is {2,4,6,…} and its gcd is 2. The chain is period two.

2.1F3F4step 1.1algebra∎

The constant vector 1=(1,1) has eigenvalue 1, while h=(1,−1) spans H0 and satisfies Ph=−h. Thus the restriction to H0 has norm 1, so [F3] gives δabs(P)=0. The eigenvalues of P are exactly 1 and −1.

Depends on

Used by

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