How statement and proof provenance work
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- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Complete-graph search matrix and gap
Example
For the complete graph search instance with any finite , let be the marked vertex and let be the uniform vector on the unmarked vertices. Compute the invariant generator matrix in the ordered basis and its eigenvalue gap. Include the boundary case . Also verify the supplied uniform preparation for and against the one- and two-qubit Hadamard circuits.
Facts & Assumptions
Given: , the encoded complete-graph adjacency, marked projector, and Hamiltonian of the algorithm.
Complete-graph continuous-time search: on the active label basis, , , and .
Graph adjacency and Laplacian generator conventions: symmetric graph adjacency is Hermitian and the ordered vertex basis is fixed.
Dirac Notation Conversion: acts by .
Finite registers and their ordered computational bases and The computational basis is orthonormal: distinct encoded labels are orthonormal basis vectors.
Exact and approximate success of complete-graph continuous-time search: with the supplied uniform preparation, exact evolution under at gives marked-label probability exactly .
Hadamard preparation of a uniform binary state: for , the standard-binary uniform state is , with Hadamard gates when primitive.
Verification
The unmarked encoded basis vectors are pairwise orthonormal by [F4], so is unit and orthogonal to the unit vector . The uniform vector is , whose squared coefficient norms sum to .
By [F1], . For , each summand contains once, so its coefficient is ; for each unmarked , the sum contains once for each , hence times. Thus .
The two vectors span an invariant subspace for by step 2.1. By [F3], and , so also preserves this span. The symmetric adjacency is Hermitian by [F2], and the generator matrix is
Put . Direct multiplication gives , and . Equivalently, its characteristic polynomial is , so its eigenvalues are . Therefore the eigenvalues of are , and their gap is .
At , is the single unmarked basis vector and the formula in step 3.1 becomes . The shifted matrix has eigenvalues , so the gap is ; all normalizations and denominators used above remain valid.
For the uniform input in step 1.1, [F5] gives marked-label probability after exact evolution at . The invariant matrix and its gap were derived locally in steps 3.1–4.1.
Specialize to the standard binary encoding for and . For , the preparation is , which is the required uniform state with one Hadamard gate. For , applying the second factor gives , the required uniform state with two Hadamard gates. These are the cases of [F6]; no preparation or gate cost is inferred from the search matrix.
Depends on
- Complete-graph continuous-time search
- Hadamard preparation of a uniform binary state
- Exact and approximate success of complete-graph continuous-time search
- Graph adjacency and Laplacian generator conventions
- Dirac Notation Conversion
- Finite registers and their ordered computational bases
- The computational basis is orthonormal
Used by
Nothing in the library uses this result yet.
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Sources
- Andrew M. Childs, Lecture Notes on Quantum Algorithms, Chapter 17 §17.1 (standard reference, not scraped)
- Ronald de Wolf, Quantum Computing: Lecture Notes, Chapter 9 §9.1 (standard reference, not scraped)