Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

VQE and MaxCut-QAOA objective calculation

Example

For VQE, take H=Z1+2Z2 and the two-qubit ansatz ∣ψ(θ,ϕ)⟩=Ry(θ)∣0⟩⊗Ry(ϕ)∣0⟩, where Ry(t)∣0⟩=cos⁡(t/2)∣0⟩+sin⁡(t/2)∣1⟩. Its energy is E(θ,ϕ)=cos⁡θ+2cos⁡ϕ. At (θ,ϕ)=(π/2,0) the energy is 2, while at (π,π) the ansatz is ∣11⟩ and reaches the ground energy −3.

For QAOA take the one-edge graph V={1,2}, E={(1,2)}, depth p=1, γ=π/2, β=π/8. Starting from ∣++⟩, the cost phase is diag⁡(1,−i,−i,1) in the order 00,01,10,11; the mixer Rx(2β)⊗Rx(2β) produces −i(∣01⟩+∣10⟩)/2. Thus the output distribution gives probability 1/2 to each cut string 01,10, zero to 00,11, and expected cut value 1.

Facts & Assumptions

Given: The Pauli matrices, the declared QAOA product order, and the finite projective measurement law.

[F1]

VQE Rayleigh–Ritz upper bound and equality case: a normalized ansatz has energy at least the least eigenvalue.

[F2]

QAOA circuit and expected combinatorial objective: the one-edge cost operator is (I−Z1Z2)/2 and the depth-one circuit order is e−iβ(X1+X2)e−iγ(I−Z1Z2)/2.

[F3]

QAOA objective is an expected feasible score only: measured bitstrings are feasible cuts and expected cut lies between feasible extrema.

[F4]

Projective measurement outcome weights are probabilities: finite projective measurement probabilities are squared basis amplitudes.

Verification

technique · direct
1.1givenF1algebra

The eigenvalues of Z1+2Z2 on ∣00⟩,∣01⟩,∣10⟩,∣11⟩ are 3,−1,1,−3, so the ground energy is −3. The product ansatz has energy cos⁡θ+2cos⁡ϕ: at (π/2,0) this is 2, and at (π,π) the state is ∣11⟩ with energy −3. Thus both the displayed trial value and attainment claim are verified.

2.1givenF2F3F4algebra∎

For QAOA, the initial state is (∣00⟩+∣01⟩+∣10⟩+∣11⟩)/2. The cost unitary multiplies only ∣01⟩,∣10⟩ by e−iπ/2=−i. With Rx(π/4)=(cos⁡(π/8)−isin⁡(π/8)−isin⁡(π/8)cos⁡(π/8)) on each wire, direct multiplication gives zero amplitudes for 00,11 and amplitude −i/2 for each of 01,10. By [F4], the probabilities are 0,1/2,1/2,0 in the stated order, so the expected cut value is 1, in agreement with [F2]–[F3].

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

28 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources