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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An out-of-bag prediction can differ from the full finite forest

Example

Take the classification sample D=((0,0),(1,1)) with ordered labels 0<1, grow depth-zero trees, and use B=2 bootstrap trees. A tree is out of bag for observation 1 exactly when its bootstrap count for training index 1 is zero. On the event that the first bootstrap count vector is (2,0) and the second is (0,2), the full forest receives one vote for each class and predicts 0 by the least-index tie rule. The out-of-bag set for observation 1 is then {2}, so its out-of-bag prediction is 1. This event has probability 1/16, and it exhibits a finite-forest out-of-bag prediction that differs from the full finite-forest prediction.

Facts & Assumptions

Given: Two independent size-2 bootstrap samples drawn uniformly with replacement from the two-observation training sample, with depth cap zero and the class tie rule in the Example.

[F1]

Bagged random-forest construction on a fixed finite sample: The out-of-bag set for observation i consists exactly of tree indices b with Nbi=0, and no prediction is returned when this set is empty.

[F2]

Empirical axis-aligned binary decision trees: A classification leaf predicts the most frequent class, choosing the least class index in a tie.

[F3]

Independent random elements have product joint law: The joint law of a finite independent family of random elements is the product of their marginal laws.

Verification

1.1givenF1F3algebra

Each tree draws two independent uniform indices from {1,2}. The probability of counts (2,0) for tree 1 is 1/4, and the probability of counts (0,2) for tree 2 is 1/4. Independence of the two trees gives probability (1/4)(1/4)=1/16 for the stated event.

2.1givenF2step 1.1

With depth cap zero, each tree is a single leaf. Its bootstrap sample contains only label 0 for counts (2,0) and only label 1 for counts (0,2), so [F2] gives predictions 0 and 1, respectively.

3.1F1step 1.1step 2.1algebra∎

The full forest has one vote for each class, so its least-index tie rule returns 0. For observation 1, the first tree has N11=2 and is excluded from the out-of-bag set, while the second has N21=0 and is the only included tree; its prediction is 1. The two predictions differ on the positive-probability event from step 1.1.

Depends on

Used by

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Sources