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ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-30
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The rank-zero bundle

Example

Let X be a scheme (Schemes and morphisms over a base) and let 0 denote the zero OX-module (Modules on a ringed space). Then:

  1. 0 is finite locally free of rank 0 (Locally free sheaves of finite rank).
  2. Its geometric total space is V(0)=Spec⁡XSym⁡(0)=X, the identity X-scheme, of rank 0 (Geometric vector bundle with the sections convention).
  3. Above each point x∈X the total space has exactly one point, the zero vector, and the module fibre 0(x) is the zero κ(x)-vector space, with exactly one element (Fibre of a module sheaf at a point, The residue field at a point of an affine scheme).

Thus rank 0 is a legitimate value of the rank function: the zero module is not excluded from the equivalence between finite locally free sheaves and geometric vector bundles, and it corresponds to the bundle whose total space is the base itself.

Facts & Assumptions

Given: A scheme X and the zero OX-module 0.

[F1]

Finite local freeness and rank (Locally free sheaves of finite rank): OX0=0 and the zero sheaf is locally free of rank 0; a locally free sheaf is quasi-coherent, its rank is well defined and locally constant, and restriction to an open subscheme preserves local freeness with the same rank.

[F2]

Geometric vector bundles (Geometric vector bundle with the sections convention): a geometric vector bundle is an affine X-scheme with a normalised grading on its relative coordinate algebra, locally graded-isomorphic to Sym⁡(OUr); its rank is the rank of the degree-one part A1; the total space of a finite locally free E is V(E)=Spec⁡XSym⁡(E∨), and for E=0 one has Sym⁡(0)=OX and V(0)=Spec⁡XOX=X with the identity structure morphism.

[F3]

Symmetric algebras (Symmetric algebra of a quasi-coherent module): Sym⁡0(F)=OX, Sym⁡1(F)=F, and Sym⁡(F) is generated in degree one, so for F=0 all positive graded parts vanish and Sym⁡(0)=OX; also Sym⁡(OXr)≅OX[T1,…,Tr] with degree-one generators, the case r=0 being OX itself.

[F4]

Relative spectra (Glue relative spectra of affine-local algebras, Affine morphisms are relative spectra): for an affine-locally module-associated algebra sheaf the relative spectrum has π−1(U)≅Spec⁡Γ(U,A) on affine U⊆X, these charts are compatible under restriction, and the structure morphism is affine with pushforward A; for A=OX each chart is Spec⁡Γ(U,OX)=U, so the relative spectrum is X with the identity morphism.

[F5]

Fibres at a point (Fibre of a module sheaf at a point, The residue field at a point of an affine scheme): the fibre of an OX-module F at x is the κ(x)-vector space F(x)=Fx⊗OX,xκ(x); for F=0 the stalk and the fibre are 0, the zero vector space with exactly one element.

[F6]

Choice accounting: the only Axiom of Choice is the one inherited from the relative-spectrum and symmetric-algebra constructions of [F2] to [F4] (The Axiom of Choice).

Proof technique: direct; compute the local freeness, the symmetric algebra, the relative spectrum and the fibres of the zero module.

Proof

1.1F1

Local freeness. On every open U⊆X the restriction of the zero module is the zero OU-module, and 0=OU0; hence the single chart U=X with r=0 satisfies the definition of finite local freeness, so 0 is finite locally free of rank 0 and quasi-coherent, with locally constant rank function 0.

1.2F3

The symmetric algebra. Sym⁡(0) has Sym⁡0(0)=OX and Sym⁡1(0)=0 and is generated in degree one; hence all its positive graded parts vanish and Sym⁡(0)=OX with degree-one part 0, the case r=0 of Sym⁡(OXr)=OX[T1,…,Tr].

1.3F2F4

The total space. The dual of the zero module is again 0, so V(0)=Spec⁡XSym⁡(0)=Spec⁡XOX; on an affine chart U=Spec⁡R⊆X the relative spectrum of OX has π−1(U)=Spec⁡Γ(U,OX)=Spec⁡R=U, with the identity transition maps on inclusions, so the glued structure morphism is the identity of X and V(0)=X.

1.4F2F3

Rank. The relative coordinate algebra of V(0) is OX with degree-one part (OX)1=0=OX0, so the rank function of this geometric vector bundle is identically 0, and dually its sheaf of sections is 0∨=0.

2.1F5step 1.3

Fibres. Since the structure morphism of V(0) is the identity, the preimage of a point x∈X is the one-point set {x}: the fibre of the bundle contains exactly one point, the zero vector, above x. On the module side the fibre of 0 at x is 0(x)=0x⊗OX,xκ(x)=0, the zero κ(x)-vector space with exactly one element, so the geometric and linear descriptions of the rank-zero fibre agree.

3.1F6step 1.1step 1.3step 1.4step 2.1∎

Conclusion and choice. The zero sheaf is finite locally free of rank 0, its total space is V(0)=X with the identity structure morphism, of rank 0, and every fibre contains exactly the zero vector; the construction uses the single chart X=U and canonical maps, so no choice beyond the inherited Axiom of Choice of [F6] is made.

Depends on

Used by

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