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A two-hop Gaussian relay with a half-bit quantization penalty

Example

Consider a real three-node relay with unit power and unit noise variance at every node, source-to-relay gain 10, relay-to-destination gain 10, and zero direct gain. Use independent X,Xr∼N(0,1), a constant reconstruction at the source, the unquantized destination output, and the fixed relay quantizer Y^r=Yr+Z^r with independent Z^r∼N(0,1). The noisy-network-coding rate for this fixed test channel is RNNC=min⁡{12log⁡26,  12log⁡211−12}=12log⁡211−12≈1.2297 bits per use. The cut-set value is 12log⁡211≈1.7297, so this fixed quantizer's NNC rate is half a bit below that outer bound.

Facts & Assumptions

Given: The three-node Gaussian relay with the stated gains, power constraints, independent inputs, and fixed quantizer.

[A1]

Assume AC (The Axiom of Choice), as required by the Gaussian coding and entropy suppliers [F2] and [F3].

[F1]

Real scalar Gaussian multicast relay network and power constraints: the channel is memoryless additive Gaussian with per-node unit power and unit noise variance.

[F2]

Noise-level noisy-network-coding inner bound for real Gaussian multicast networks: for a cut A and destination d, NNC subtracts I(YA;Y^A∣X[N],Yd,Y^Ac) from I(XA;Yd,Y^Ac∣XAc); constant reconstructions are allowed.

[F3]

Gaussian maximizes differential entropy at fixed positive-definite covariance: Gaussian laws maximize differential entropy at fixed covariance, so the cut mutual informations are bounded by the corresponding Gaussian log expressions.

Proof

1.1A1F1givenalgebra

Assume [A1] and use the independent unit-variance Gaussian inputs and quantizer noise stated in the example. For the cut separating the source alone, the relay sees 10X+Zr, and adding independent unit-variance quantization noise makes total noise variance 2. Thus the NNC first-cut mutual information is 12log⁡2(1+10/2)=12log⁡26. The destination has no direct source term, so its observation adds zero information across this cut.

1.2F1F2givenalgebra

For the cut containing source and relay, the destination observes 10Xr+Zd, so I(X,Xr;Yd)=12log⁡2(1+10)=12log⁡211. Given all inputs and Yd, the relay observation noise and independent quantization noise have variances 1 and 1, hence I(Yr;Y^r∣X,Xr,Yd)=12log⁡2(2)=12. The two NNC cut rates are therefore the values in the minimum in the statement.

2.1F1F2F3step 1.1step 1.2algebra∎

The first cut is larger because 6>11/2 (equivalently 12>11), so the minimum is 12log⁡211−12. In the cut-set expression, the source cut is I(X;Yr,Yd∣Xr)=I(X;Yr∣Xr)≤12log⁡211 and the relay-to-destination cut is I(X,Xr;Yd)=I(Xr;Yd)≤12log⁡211, since the direct gain is zero; [F3] gives each Gaussian upper bound. Independent unit-power Gaussian inputs attain both terms, so the cut-set value is 12log⁡211. Subtracting gives a gap of exactly 1/2 bit.

Scope note

This is the rate of the stated fixed quantizer, not the optimized NNC rate. The general reconstruction-set coding statement [F2], with only the relay quantized, proves achievability of every strict rate below the displayed value and its closure.

Depends on

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