Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

residue field infinite projective dimension singular

Example

Let k be a field. For R=k[ε]/(ε2), its residue field k has an infinite minimal free resolution with one copy of R in every degree and every positive differential multiplication by ε. Consequently βiR(k)=1 for all i0 and pdRk=.

Facts & Assumptions

Given: The objects and hypotheses in the example. We work with the Axiom of Choice; cited dependent-choice and resolution-existence hypotheses are retained.

[F1]

projective dimension from last nonzero betti number: For a nonzero finite module M over a nonzero Noetherian local ring, pdRM=sup{i0:βiR(M)0}, allowing infinity. For each integer q0, pdRMq if and only if Torq+1R(k,M)=0.

[F2]

betti number is rank in minimal resolution: For every minimal degreewise finite free resolution FM of a finite module over a nonzero Noetherian local ring, βiR(M)=rankRFi for all i0.

Verification

1.1

The ring is local with maximal ideal (ε). For multiplication by ε, the image and kernel both equal (ε): ε(a+bε)=aε. The augmentation Rk has that same kernel. Thus the infinite augmented complex is exact in every degree and all positive matrix entries are in the maximal ideal.

givenalgebra
2.1

The rank formula gives βi(k)=1 in every degree. These nonzero Betti numbers are unbounded in degree, so the projective-dimension criterion gives infinity. A finite initial truncation would have a nonzero left kernel and is not a finite resolution.

F2F1step 1.1

Depends on

Used by

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Sources