Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck passverified 2026-09-23 (gpt-6-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

residue field infinite projective dimension singular

Example

Assume the Axiom of Choice. Let k be a field. For R=k[ε]/(ε2), its residue field k has an infinite minimal free resolution with one copy of R in every degree and every positive differential multiplication by ε. Consequently βiR(k)=1 for all i≥0 and pd⁡Rk=∞.

Facts & Assumptions

Given: The objects and hypotheses in the example. We work with the Axiom of Choice; cited dependent-choice and resolution-existence hypotheses are retained.

[F1]

projective dimension from last nonzero betti number: For a nonzero finite module M over a nonzero Noetherian local ring, pd⁡RM=sup⁡{i≥0:βiR(M)≠0}, allowing infinity. For each integer q≥0, pd⁡RM≤q if and only if Tor⁡q+1R(k,M)=0.

[F2]

betti number is rank in minimal resolution: For every minimal degreewise finite free resolution F∙→M of a finite module over a nonzero Noetherian local ring, βiR(M)=rank⁡RFi for all i≥0.

Verification

1.1givenalgebra

The ring is local with maximal ideal (ε). For multiplication by ε, the image and kernel both equal (ε): ε(a+bε)=aε. The augmentation R→k has that same kernel. Thus the infinite augmented complex is exact in every degree and all positive matrix entries are in the maximal ideal.

2.1givenF2F1step 1.1∎

Under the stated AC premise, the rank formula gives βi(k)=1 in every degree. These nonzero Betti numbers are unbounded in degree, so the projective-dimension criterion gives infinity. A finite initial truncation would have a nonzero left kernel and is not a finite resolution.

Depends on

Used by

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Dependency tree · two levels

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Sources