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ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-27
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A right-flat tensor bimodule can have nonprojective output

Example

Let k be a field, let A=k with its trivial grading and let B=k[ε]/(ε2) with ε placed in degree 0, so that B is a graded k-algebra concentrated in degree 0. Let π:B↠k be the augmentation with π(ε)=0, and let M=k be the graded (B,A)-bimodule concentrated in degree 0 whose left B-action is b⋅m:=π(b)m and whose right k-action is ordinary multiplication.

Then M is flat as a right k-module, so M⊗k− is exact, but the left B-module M⊗kk≅k is not projective. Thus right A-flatness of the bimodule does not imply that its tensor functor carries finite graded projectives to projective outputs.

Facts & Assumptions

Given: A field k, the graded k-algebras A=k and B=k[ε]/(ε2) in degree 0, the augmentation π:B→k, and the graded (B,A)-bimodule M=k with b⋅m=π(b)m and m⋅λ=mλ.

[L1]

Graded algebras, graded modules and degree-zero maps are defined in Associative graded algebras, bimodules, and internal shifts; since every module here is concentrated in degree 0, all module maps are degree-zero.

[L2]

The tensor product of graded modules carries the total-degree grading and the outer action b(m⊗n)=(bm)⊗n (Graded balanced tensor product and homogeneous Hom).

[L3]

If M is flat as a right A-module then M⊗A− is exact, and if M is finite graded projective as a left B-module then M⊗A− preserves finite graded projectives (Bimodule tensor exactness and preservation of finite projectives have separate hypotheses).

[L4]

Projective objects have the lifting property, and a finite direct sum of shifts B{s1}⊕⋯⊕B{sn} is finite graded projective (Finite graded projectives are finite shifted-free summands).

Verification

1.1

The two actions on M commute: (b⋅m)⋅λ=π(b)mλ=b⋅(mλ), and each is additive and unital, so M is a (B,A)-bimodule; both actions preserve the degree-0 part because π and the scalar action do, so M is a graded bimodule.

L1
1.2

M=k is a free right k-module of rank one, hence flat, so M⊗k− is exact; equivalently the functor is k⊗k−, which is naturally the identity on k-vector spaces.

L3
1.3

The unit isomorphism M⊗AA→M, m⊗λ↦mλ, identifies M⊗kk with k, and under this identification the left B-action is b⋅(m⊗λ)=bm⊗λ, i.e. the action of B on k through π; so M⊗kk≅k as graded left B-modules.

L2
1.4

The module k=B/(ε) is not projective as a left B-module. The quotient map π:B↠k=B/(ε) is B-linear and degree-zero; if k were projective, its lifting property against π and the identity of k would produce a B-linear section s:k→B with πs=1k. Writing u:=s(1) one has π(u)=1, so u=1+cε for some c∈k, and B-linearity gives εu=s(ε⋅1)=s(0)=0, whereas εu=ε+cε2=ε≠0. This contradiction shows that no such section exists, so k is not projective over B.

L1L3L4
2.1

Steps 1.2 and 1.3 give a right-flat bimodule M whose tensor functor is exact and whose value on the finite graded projective left A-module A=k is M⊗kk≅k; by step 1.4 that output is not projective as a left B-module, and it is not a finite graded projective module either. Hence the exactness hypothesis of [L3] does not deliver its projectivity conclusion, which is why that conclusion carries the separate hypothesis that M be finite graded projective over B — a hypothesis M fails by step 1.4.

step 1.2step 1.3step 1.4L3L4
3.1

The example therefore exhibits a right-flat tensor bimodule whose tensor functor is exact but which produces a nonprojective, non-finite-projective output from a finite graded projective input. ∎

step 2.1

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