Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Separated and nonseparated initial supports

Example

Assume AC. In Ω=R2, let σ be normalized arc-length probability on the unit circle S1={x:∣x∣=1} and let δ0 be the point mass at the origin. For radii ra=1/2 and rb=2, the support of σ is contained in the ball B(0,rb) and separates the two spheres raS1 and rbS1: every continuous path from one sphere to the other meets S1. In contrast, the support of δ0 is contained in B(0,rb) but does not separate those spheres. These are only checks of the topological initialization condition; neither example asserts that any flow converges or that its limit is globally minimizing.

Facts & Assumptions

Given: AC and the two probability measures in the Example.

[F1]

The support of a finite Borel measure is the closed set of points whose every open neighborhood has positive measure. Support of a finite Borel measure on the plane

Proof

Given: The measures and radii in the Example.

1.1F1given

Every open ball centered at a point of S1 intersects an arc of positive arc length, so [F1] gives supp⁡σ=S1. Since every point of S1 has norm 1<2, the support lies in B(0,2).

2.1F2step 1.1

Let γ:[0,1]→R2 be continuous with ∣γ(0)∣=1/2 and ∣γ(1)∣=2. The scalar map t↦∣γ(t)∣ is continuous because ∣∣x∣−∣y∣∣≤∣x−y∣. By [F2], it equals 1 for some t, so γ(t)∈S1 and the support separates the two spheres.

3.1F1given∎

The support of δ0 is {0} by [F1]. The radial segment γ(t)=((1−t)/2+2t,0) joins (1/2,0) to (2,0) and has strictly positive norm throughout, so it avoids {0}. Thus this support does not separate the spheres. No conclusion about energy minimizers follows from either topological calculation.

Depends on

Used by

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Dependency tree · two levels

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Sources