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The signed measure with density sin x on [0,2pi] exhibits the nonuniqueness of Hahn decompositions
Example
Let be Lebesgue measure on and define Then is a Hahn decomposition, and so is because the points and are -null.
Facts & Assumptions
Given: The signed measure on .
A real density defines a finite signed measure whose canonical Hahn sets are and . (A real L^1 density defines a finite signed measure with its canonical Hahn and Jordan data)
Hahn decompositions are unique only up to null sets. (Hahn decomposition for signed measures, unique up to total-variation-null sets)
On , one has on , on , and exactly at .
Verification
By [A1], the density theorem [L1] makes positive and negative for . Thus is a Hahn decomposition.
The points and are -null because there. Moving those null points from to preserves positivity and negativity, so is another Hahn decomposition. It is distinct from and compatible with the uniqueness clause of [L2].
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Richard F. Bass, Real Analysis for Graduate Students, Example 12.3 (standard reference, not scraped)