Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passaudited 2026-08-30
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The signed measure with density sin x on [0,2pi] exhibits the nonuniqueness of Hahn decompositions

Example

Let λ be Lebesgue measure on [0,2π] and define ν(E):=Esinxdλ(EB([0,2π])). Then P0=(0,π),N0={0}[π,2π] is a Hahn decomposition, and so is P1=[0,π],N1=(π,2π], because the points 0 and π are ν-null.

Facts & Assumptions

Given: The signed measure ν(E)=Esinxdλ on [0,2π].

[L1]

A real L1 density defines a finite signed measure whose canonical Hahn sets are {f>0} and {f0}. (A real L^1 density defines a finite signed measure with its canonical Hahn and Jordan data)

[L2]

Hahn decompositions are unique only up to null sets. (Hahn decomposition for signed measures, unique up to total-variation-null sets)

[A1]

On [0,2π], one has sinx>0 on (0,π), sinx<0 on (π,2π), and sinx=0 exactly at 0,π,2π.

Verification

technique · direct
1.1

By [A1], the density theorem [L1] makes (0,π) positive and {0}[π,2π] negative for ν. Thus P0,N0 is a Hahn decomposition.

L1A1
2.1

The points 0 and π are ν-null because sinx=0 there. Moving those null points from N0 to P1 preserves positivity and negativity, so P1,N1 is another Hahn decomposition. It is distinct from P0,N0 and compatible with the uniqueness clause of [L2].

L2A1step 1.1

Depends on

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