How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A set-valued skyscraper sheaf and its stalks
Example
Fix a point and a set . Define a presheaf by with identity restrictions between opens containing and the unique map to when the target does not contain . Then is a sheaf. Its stalk at is canonically , and its stalk at any with an open neighbourhood satisfying is the singleton . In particular, this holds for every in a space.
Facts & Assumptions
Given: A point , a set , and a point . For the second stalk computation, also assume has an open neighbourhood with .
The sheaf condition is locality and unique gluing on open covers (A sheaf on a topological space).
Stalks are colimits over neighbourhoods, and germs are represented by local sections (The stalk of a presheaf at a point, Germs of sections).
Verification
If an open set does not contain , then every section of is the unique element , so locality and gluing are trivial. If and , then at least one contains . Compatibility forces all sections on such to be the same element of , and every not containing contributes only the unique section . Thus there is a unique glued section on . Therefore [L1] holds and is a sheaf.
For the stalk at , every neighbourhood of has section set and every transition map is the identity on . Hence the colimit in [F1] is canonically .
If has an open neighbourhood with , then every smaller neighbourhood of inside also has section set . Hence the stalk diagram is eventually constant at , so [F1] gives .
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- The Stacks Project, Sheaves on Spaces, Section 27 (standard reference, not scraped)