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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A three-unit SRSWOR variance calculation

Example

Let U={1,2,3} with fixed values y=(1,2,4), and select an SRSWOR sample of size n=2. The three samples each have probability 1/3. Their Horvitz–Thompson totals are 9/2, 15/2, and 9, respectively, so the true design variance of the total is 7/2. The pair-inclusion and Sen–Yates–Grundy sample estimates are 3/4, 27/4, and 3; their mean is also 7/2. The sample means are 3/2, 5/2, and 3, with variance 7/18. The finite support of three values is not an exact normal law.

Samplepd(s)T^HTV^HTV^SYGyˉs
{1,2}1/39/23/43/43/2
{1,3}1/315/227/427/45/2
{2,3}1/39333

Facts & Assumptions

Given: U={1,2,3}, y1=1,y2=2,y3=4, and SRSWOR of size two.

[F1]

Simple random sampling without replacement: The support consists of all two-element subsets, each with probability 1/(32)=1/3.

[F2]

Horvitz–Thompson variance and pair-inclusion estimate: If πi>0, the total variance is ∑i,jΔijyiyj/(πiπj); if all πij>0, the pair-inclusion estimate has expectation equal to that variance.

[F3]

Sen–Yates–Grundy variance identity: For a fixed-size design, Var⁡d(T^HT)=−12∑i,jΔij(yi/πi−yj/πj)2, and the sample pair-inclusion version is unbiased when every πij>0.

[F4]

SRSWOR inclusion covariance and sample-mean variance: For N>1 and 1≤n≤N, Var⁡d(yˉS)=(1−n/N)SU2/n.

Verification

1.1givenF1choosealgebra

By [F1], the support is {{1,2},{1,3},{2,3}} with equal probabilities. Counting occurrences gives πi=2/3, πij=1/3 for i≠j, Δii=2/9, and Δij=−1/9 for i≠j; the population mean is 7/3 and SU2=((1−7/3)2+(2−7/3)2+(4−7/3)2)/2=7/3.

2.1givenF1F2step 1.1algebra

Each observed total is (3/2) times the sum of the two observed values, so the HT totals are 9/2,15/2,9 and have mean 7; their design variance is 13((9/2−7)2+(15/2−7)2+(9−7)2)=7/2.

2.2F1F2F3step 1.1algebra

Put xi=yi/πi, so (x1,x2,x3)=(3/2,3,6). For any sampled pair {i,j}, the HT pair estimate and the SYG estimate both equal 13(xi−xj)2, since Δii/πi=1/3 and Δij/πij=−1/3; thus they are 3/4,27/4,3 and their expectation is 13(3/4+27/4+3)=7/2 by [F2] and [F3].

3.1F1F4step 1.1algebra∎

The sample means are 3/2,5/2,3, with average 7/3 and design variance 13((3/2−7/3)2+(5/2−7/3)2+(3−7/3)2)=7/18; [F4] gives (1−2/3)(7/3)/2=7/18, and the three supported means form a finite set rather than an exact normal calibration.

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