Alphabeta Math
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A system of parameters need not minimally generate the maximal ideal

Example

Let

R=k[x,y](x,y)/(y2x3).

Then R has dimension 1, the ideal (xˉ) is a parameter ideal, but the maximal ideal m=(xˉ,yˉ) is not generated by one element.

Facts & Assumptions

Given: A field k and the cusp local ring R=k[x,y](x,y)/(y2x3) with maximal ideal m=(xˉ,yˉ).

[L1]

A parameter ideal in a one-dimensional local ring is exactly a one-generated ideal with maximal radical (Systems of parameters and parameter ideals, Parameter ideals are exactly the m-primary d-generated ideals).

[L2]

The dimension of a Noetherian local ring is the least number of generators of an ideal with maximal radical (Local dimension is the minimal number of generators of an ideal with maximal radical).

[L3]

A Noetherian local domain has dimension zero exactly when it is a field (A Noetherian local domain has dimension zero exactly when it is a field).

Verification

technique · direct computation
1.1

The quotient R/(xˉ)k[y](y)/(y2) is Artinian local, so (xˉ) has radical m. Thus there exists a one-generated ideal with maximal radical, and [L2] gives dimR1.

L2given
1.2

If m were principal, then m/m2 would be one-dimensional over the residue field. But the classes of xˉ and yˉ are linearly independent modulo m2, so m is not principal. In particular m(0), so R is not a field.

givenalgebra
2.1

Since R is a local domain and not a field, [L3] shows that dimR0. Together with step 1.1, this forces dimR=1. Then [L1] makes (xˉ) a parameter ideal.

L1L3step 1.1step 1.2
3.1

Therefore (xˉ) is a parameter ideal while m is not principal, so a system of parameters need not minimally generate the maximal ideal.

step 1.2step 2.1

Depends on

Used by

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Sources